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Zigmanuir [339]
2 years ago
8

6th grade math help me pozzzz

Mathematics
1 answer:
Sonja [21]2 years ago
3 0

Answer:

t= -9/10= -0.900

Step-by-step explanation:

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Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

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P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

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Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

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\dfrac{3m+3n}{3}=\dfrac{-18}{3}

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2 years ago
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kvv77 [185]
<span>[x + 2 - (5x + 5)] ² =
[x + 2 - 5x - 5]² =
[x - 5x + 2 - 5]² =
[-4x - 3]² =
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Answer:
</span>\boxed{C = 16x^2 + 24x + 9}<span>



</span>
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