Find the missing number so that the equation has infinitely many solutions.
1 answer:
You might be interested in
<u>ANSWER: </u>
The solution of the two equations 2x+3y=5 and 4x - y=17 is (4, -1).
<u>SOLUTION: </u>
Given, two linear equations are 2x + 3y = 5 → (1) and 4x – y = 17 → (2).
Let us first solve the above equations using <em>elimination process. </em>
For elimination, one of the coefficients of variables has to be same in order to cancel them.
Now solve (1) and (2)
eqn (1) 2 → 4x + 6y = 10
eqn (2) → 4x – y = 17
(-) ----------------------------
0x + 7y = -7
y = -1
Substitute y value in (2)
So, solution of two equations is (4, -1).
<u><em>Now let us solve using substitution process.</em></u>
Then, (2) → 4x – y = 17 → 4x = 17 + y → y = 4x – 17
Now substitute y value in (1) → 2x + 3(4x – 17) = 5 → 2x + 12x – 51 = 5 → 14x = 5 + 51 → 14x = 56
x = 4
Substitute x value in (2) → y = 4(4) – 17 → y = 16 – 17 → y = -1
Hence, the solution of the two equations is (4, -1).
Answer:
17)
18)
19) 14x³y²
20) π
Step-by-step explanation:
17)
Area of triangle = 1/2*b*h
A = 1/2(4a²b)(3ab)
A = 6(a³b²)
18)
A = 1/2(4mn⁵)(20m³n⁵)
A = (40)(m⁴n¹⁰)
19)
A = 2 (1/2)(2xy)(3x²y)
A = (6x³y²) + (4x²y*2xy)
A = 6x³y² + 8x³y²
A = 14x³y²
20)
A = (3xy³)²
A = 3² x² (y³)²