We want to find the total number of integers that are larger than 40 and smaller than 99 that also are multiples of 3.
The answer is 18.
We can solve this just by counting.
The first multiple of 3 larger than 40 is:
3*14 = 42
Now we know that 99 is also a multiple of 3 and that the multiples of 3 are separated by a distance of 3 units, then the total number of multiples of 3 between 42 and 99 is given by:
(99 - 42)/3 = 19
But we need to remove 1, because we used 99 and we have the restriction that our numbers must be "smaller" than 99.
Then we have a total of 18 multiples of 3 between 40 and 99.
If you want to learn more, you can read:
brainly.com/question/19239363
