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Fittoniya [83]
2 years ago
11

Jimmy held the end of a metal bar over a fire while holding on to the opposite end. After a few minutes, the end he was holding

began to get very hot. Which of the following processes correctly describes the heat traveling from one end of the bar to the other?
Physics
1 answer:
nikitadnepr [17]2 years ago
6 0

Answer:

Hey mate....

Explanation:

This is ur answer....

<em></em>

<em>The heat is transferred by the process of conduction of heat. </em>

<em> It is given that, Jimmy held the end of a metal bar over a fire while holding on to the opposite end.     </em>

<em> After some time, the end he was holding began to get very hot. </em>

<em> The process of traveling heat from one end of the bar to the other end is called conduction. It is the process of transfer of heat by the interaction of particles and motion of electrons.</em>

<em></em>

Hope it helps!

Brainliest pls!

Follow me! :)

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6 0
3 years ago
A meter stick moves parallel to its axis with speed of 0.96 c relative to you. What would you measure for the length of the stic
Fed [463]

Answer:

The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

Explanation:

Given that,

Relative speed of stick v= 0.96 c

Speed of light c= 2.99793\times10^{8}\ m/s

Proper length of stick = 1 m

We need to calculate the length of the stick

Using formula of length

\Delta l=\Delta l_{0}\sqrt{(1-\dfrac{v^2}{c^2})}

Put the value into the formula

\Delta l=1\sqrt{1-\dfrac{(0.96)^2c^2}{c^2}}

\Delta l=1\sqrt{1-(0.96)^2}

\Delta l=0.28\ m

We need to calculate the time the stick take to move

Using formula of time

t=\dfrac{\Delta l}{v}

Put the value into the formula

t=\dfrac{0.28}{0.96\times(2.99793\times10^{8})}

t=9.72\times10^{-10}\ sec

t=0.97\ ns

Hence, The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

7 0
3 years ago
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