The range of a projectile is the maximum horizontal distance between the point of origin to the end point. It can be calculated through the equation,
range = v²sin2θ/g
where v is the initial velocity, θ is the angle, and g is the gravitational constant.
Substituting the known values,
range = (36 m/s)² x (sin2(28°)) / 9.8 m/s²
range = 109.64 m
Thus, the range of the golf ball is approximately 109.64 m.
Answer:
<h3>4.13m</h3>
Explanation:
Given
Horizontal velocity = 9.00m/s
time taken = 0.550 s
Required
How far does the projectile fall in the vertical direction
Using the formula for finding the maximum height of the projectile
H = U²sin²θ/2g where;
U = 9.00m/s
θ = 90° (object launched in the vertical direction)
g = 9.81m/s²
Substituting the given parameters into the formula;
H = 9²sin²90/2(9.81)
H = 81(1)/19.62
H = 81/19.62
H = 4.128 m
H ≈ 4.13m
Hence the distance that the projectile fall in the vertical direction is 4.13m