Answer:
Initial pressure = 6 atm. Work = 0.144 J
Explanation:
You need to know the equation P1*V1=P2*V2, where P1 is the initial pressure, V1 is the initial volume, and P2 and V2 are the final pressure and volume respectively. So you can rearrange the terms and find that (1.2*0.05)/(0.01) = initial pressure = 6 atm. The work done by the system can be obtained calculating the are under the curve, so it is 0.144J
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13 g —> 0.013 kg
KE = 1/2(m)(v)^2
KE = 1/2(0.013)(8.5)^2
KE = 0.47 J
The answer should be speed hope this helps
Answer:
The energy stored is: 62.5 Joules
Explanation:
Given
--- spring constant
--- stretch
Required
The amount of energy
This is calculated as:
The last equation gives you the tension in the string on the right:
