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LUCKY_DIMON [66]
2 years ago
8

A baseball (m=145g) traveling 39 m/s moves a fielder's glove backward 23 cm when the ball is caught.

Physics
1 answer:
Grace [21]2 years ago
5 0

The average force exerted by the ball on the glove is 480 N.

<h3>What is the force exerted by the ball on the glove?</h3>

The average force exerted on the glove by the ball is equal in magnitude to the force on the ball.

  • Force = mass * acceleration

mass = 145 g = 0.145 kg

Acceleration of the baseball, a = (v² - u²)/2s

where:

v is final velocity = 0

u is initial velocity = 39 m/s

s is distance = -23 cm = 0.23 m

a = (0 - 39²)/2(-0.23)

a = 3306.52 m/s²

Force = 0.145 * 3306.52

Force = 479.4 N

Average force = 480 N

In conclusion, force is derived from the product of mass and acceleration.

Learn more about force at: brainly.com/question/12970081

#SPJ1

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spin [16.1K]

Answer :  <em>Her weight is lower on Venus because the acceleration due to gravity is lower.</em>

Explanation :

Venus is also called as Earth's twin. This is because both the mass and the size of Earth and Venus are almost same. The acceleration due to gravity on earth is 9.8\ m/s^2 while on Venus is 8.87\ m/s^2.

So, when Shari measure her weight on Venus she found her weight is lower on Venus. This is because the acceleration due to gravity is lower on the surface of Venus as compared to the Earth.

Since,    w=mg

i.e. weight depends on g.

<em>So, correct prediction is (b)</em>

3 0
3 years ago
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What % of an object’s mass is above the water line if the object’s density is 0.82g/ml?
Sladkaya [172]

To develop this problem we will apply the Archimedes model. As well as the definitions of Weight based on mass and acceleration. The first in turn will be considered under the relationship of Density and Volume. From the values given we have to:

\rho_w =1 g/mL \rightarrow \text{Water Density}

\rho_o = 0.82g/mL \rightarrow \text{Object density}

Since it is in equilibrium, the weight of the object will have a reaction from the water, which will cause the sum of forces between the two objects to be zero, therefore

\sum F= 0

F_w-F_o = 0

F_w = F_o

m_w g = m_og

\rho_w V_w g = \rho_o V_o g

The value of gravity is canceled because it is a constant

\frac{V_w}{V_o} = \frac{\rho_o}{\rho_w}

\frac{V_w}{V_o} = \frac{0.82}{1}

\frac{V_w}{V_o} = 0.82

The portion of the object that is submerged corresponds to 82%, while the portion that is visible, above the water level will be 18%

4 0
3 years ago
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Answer:

1. a

2. a [im iffy on this but 95% positive its this]

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Explanation:

3 0
2 years ago
Three collinear forces,F1=45N west,F2=63N east and an unknown force F3 are applied to an object.The resultant force of the three
Greeley [361]

Take east to be the positive direction. Then the resultant force from adding <em>F</em>₁ and <em>F</em>₂ is

<em>F</em>₁ + <em>F</em>₂ = (-45 N) + 63 N = 18 N

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To this we add a third force <em>F</em>₃ such that the resultant is 12 N pointing west, making it negative, so that

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6 0
3 years ago
A student constructed a series circuit consisting of a 12.0-volt battery, a 10.0-ohm lamp, and a
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i= \frac{V}{R_{eq}}  \\ 0.5= \frac{12}{R+10}  \\ R+10=24 \\ R=14-Ohm
 
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R_{eq}=R+10 \\ R_{eq}=14+10 \\ \boxed {R_{eq}=24-Ohm}

If you notice any mistake in my english, please let me know, because i am not native.

6 0
3 years ago
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