Answer:

Step-by-step explanation:
The perimeter of a polygon is equal to the sum of all the sides of the polygon. Quadrilateral PTOS consists of sides TP, SP, TO, and SO.
Since TO and SO are both radii of the circle, they must be equal. Thus, since TO is given as 10 cm, SO will also be 10 cm.
To find TP and SP, we can use the Pythagorean Theorem. Since they are tangents, they intersect the circle at a
, creating right triangles
and
.
The Pythagorean Theorem states that the following is true for any right triangle:
, where
is the hypotenuse, or the longest side, of the triangle
Thus, we have:

Since both TP and SP are tangents of the circle and extend to the same point P, they will be equal.
What we know:
Thus, the perimeter of the quadrilateral PTOS is equal to 
Answer:
m = -8
b = -24
Step-by-step explanation:
To solve this problem use the hint and put this equation in y = mx + b form. This is called slope-intercept form.
In slope-intercept form, the coefficient of x (which is m) is the slope of the line and b is the y-intercept of the line.
Add 32x to both sides of the equation.
Divide both sides of the equation by -4.
Comparing this to y = mx + b, the -8 is "m" and -24 is "b". Therefore your final answers are:
m = -8
b = -24
Answer:
-12 = p
Step-by-step explanation:
Isolate the p terms on one side and the constants on the other side. Subtract 5p from both sides: 10 = p + 22. Next, subtract 22 from both sides, obtaining
-12 = p
<span>−6/11 ⋅ 3/4
= -3/11 </span>⋅ 3/2
= -9/22
hope it helps