Answer:
2x + y = 3 becomes y = 3 - 2x
-2x + y = -1 becomes y = -1 + 2x
2x + y = 5 becomes y = 5 - 2x
Parallel: 2x + y = 5
Perpendicular: 0.5x + 7
neither parallel nor perpendicular to line a: -2x + y = -1
Answer:
can you show me picture it would help a lot so i can help you
Step-by-step explanation:
Answer:
a 10 yd 2ft 7 in
b 10 yd 1 ft 2 in
c 99 yd
d. 4840 sq yd 7 sq ft 119 sq in
Step-by-step explanation:
a. 2 ft. 5 in. +
9 yd. 3 ft. 2 in.
---------------------
9 yd 5ft 7 in
but 3 ft = 1yd
9 yd 5ft 7 in
+1yd - 3ft
---------------------------
10 yd 2ft 7 in
b. 4 yd. 8 in
+ 6 yd. 6 in.
----------------------
10 yd 14 in
but 12 in = 1ft
10 yd 14 in
+ 1ft - 12 in
---------------------
10 yd 1 ft 2 in
c. 29 yd. 2 ft. 11 in.
55 yd. 1 ft. 10 in.
+ 13 yd. 1 ft. 3 in.
--------------------------
97 yd 4 ft 24 in
12 in = 1ft
24 in = 2ft
97 yd 4 ft 24 in
+2ft - 24 in
--------------------------------
97 yd 6ft
3 ft = 1yd
6f = 2yd
97 yd 6ft
+2yd - 6ft
---------------------
99 yd
d. 4,839 sq. yd. 8 sq. ft. 139 sq. in.
+ 7 sq. ft. 124 sq. in.
--------------------------------------------------
4839 sq yd 15 sq ft 263 sq in
12*12 = 144 sq in = 1 sq ft
4839 sq yd 15 sq ft 263 sq in
+ 1 sq ft - 144 sq in
--------------------------------------------------
4839 sq yd 16 sq ft 119 sq in
3ft * 3 ft = 9 sq ft = 1 sq yd
4839 sq yd 16 sq ft 119 sq in
+1 sq yd - 9 sq ft
----------------------------------------------
4840 sq yd 7 sq ft 119 sq in
<span><span>1.
</span>Given numbers:
74 % of 315
89% of 195
now, let’s solve the first given numbers:
=> 74% of 315
=> 315 is the 100%
Let’s convert 74% into decimals
=> 74% = .74
=> 315 * .74 = 233.1, the value of 74% of 315
Let’s solve the second given:
=> 89% of 195
where 195 is the 100%
=> 89% = .89
=> 195 * .89
=> 173.55, the value of 89% of 195</span>
Yes I think you are correct. The domain appears to be the set of x values such that -4 < x < 3 meaning that x is between -4 and 3, excluding each endpoint. In interval notation, that translates to (-4, 3). This of course assumes that we have two vertical asymptotes bookending the left and right sides of the curve, and these vertical asymptotes are at x = -4 and x = 3. If the curve extends beyond these boundaries, then the domain would instead be the set of all real numbers.