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Rina8888 [55]
2 years ago
12

Find the area of this triangle, round to the nearest tenth. I will give brainliest

Mathematics
1 answer:
USPshnik [31]2 years ago
5 0

Answer:

108.8yd²

Step-by-step explanation:

Area of a Side Angle Side triangle : Area = 1/2 ( a × b ) × sin(c)

where a and b = the side lengths and c = the angle

Here the given side lengths are 23yds and 9.5yds and the angle given has a measure of 85° so a = 23, b = 9.5 and c = 85

Area = = 1/2 ( a × b ) × sin(c)

a = 23 , b = 9.5 and c = 85

Area = 1/2 ( 23 × 9.5 ) × sin(85)

==> multiply 23 and 9.5

Area = 1/2 ( 218.5 ) × sin(85)

==> multiply 1/2 and 218.5

Area = 109.25 × sin(85)

==> multiply sin(85) and 109.25

Area = 108.8yd²

Note: When the triangle is not a right triangle ( when there is no 90° angle ) we have to use a special formula in order to find the area. Here this is given a side an angle and a side, when given a side an angle and another side you can solve using the formula Area = 1/2 ( a × b ) × sin(c)

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Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
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