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2 years ago

Find the area of this triangle, round to the nearest tenth. I will give brainliest

Mathematics

1 answer:

USPshnik [31]2 years ago

5 0

Answer:

108.8yd²

Step-by-step explanation:

Area of a Side Angle Side triangle : Area = 1/2 ( a × b ) × sin(c)

where a and b = the side lengths and c = the angle

Here the given side lengths are 23yds and 9.5yds and the angle given has a measure of 85° so a = 23, b = 9.5 and c = 85

Area = = 1/2 ( a × b ) × sin(c)

a = 23 , b = 9.5 and c = 85

Area = 1/2 ( 23 × 9.5 ) × sin(85)

==> multiply 23 and 9.5

Area = 1/2 ( 218.5 ) × sin(85)

==> multiply 1/2 and 218.5

Area = 109.25 × sin(85)

==> multiply sin(85) and 109.25

Area = 108.8yd²

Note: When the triangle is not a right triangle ( when there is no 90° angle ) we have to use a special formula in order to find the area. Here this is given a side an angle and a side, when given a side an angle and another side you can solve using the formula Area = 1/2 ( a × b ) × sin(c)

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Question 1 (1 point)

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1) $2y^{2}+4y-9$

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Step-by-step explanation:

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$(y^{2}-3y-5)-(-y^{2}-7y+4)=y^{2}-3y-5+y^{2}+7y-4=2y^{2}+4y-9$

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$(6xy^{3}z)(3x^{2}yx^{2})=18x^{5}y^{4}z$

3) Apply the Distributive property and the Product property of exponents. Then, you obtain:

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