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3 years ago

I will mark brainlist for correct answer

Mathematics

1 answer:

Vlada [557]3 years ago

6 0

Answer:

neither
arithmetic
geometric
arithmetic
geometric

Step-by-step explanation:

Arithmetic sequences have a common difference. Geometric sequences have a common ratio.

The difference is found by subtracting a term from the next. If successive differences are all the same, they are "common."

The ratio is found by dividing a term by the one before it. If successive ratios are all the same, they are "common."

There is no common ratio or common difference: neither.

The common difference is 14: arithmetic.

The common ratio is -2: geometric.

The common difference is -6: arithmetic.

The common ratio is 1/8: geometric.

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To answer this problem we have to have a <span>Standard Normal Distribution table because we need to look up z scores. Then we use this equation
</span><span>z = (value - mean)/(standard deviation) = (250-200)/20 = 2.5.
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The z score is then 2.5 </span>If so, look up z=2.5 on the left edge then you then determine from the table what the area to the left of that is.
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3 years ago

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3 years ago

An online retailer collects 7% sales tax. If the sub total of the purchase is $76.00, then how much is collected for sales tax?

jok3333 [9.3K]

The collected tax on purchase of $76.00 is $5.32

Further explanation:

The sales tax is calculated on the total sales by the formula

$Tax = total * \frac{7}{100}$

Given

Total purchase = $76.00

Percentage of tax = 7%

So,

Putting the values in the formula

$Tax\ amount = 76.00 * \frac{7}{100}\\= 5.32$

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3 years ago

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Murrr4er [49]

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3 years ago

Iron deficiency anemia is an important nutritional health problem in the U.S. A dietary assessment was performed on 51 boys 9-11

Bond [772]

Answer:

a) Null hypothesis: $\mu = 14.44$

Alternative hypothesis: $\mu \neq 14.44$

b) $t=\frac{12.50-14.44}{\frac{4.75}{\sqrt{51}}}=-2.917$

The degrees of freedom are given by:

$df =n-1= 51-1=50$

Now we can calculate the p value taking in count the alternative hypothesis

$p_v =2*P(t_{50}$

Since the p value is lower than the significance $\alpha=0.05$ we have enough evidence to reject the null hypothesis and the true mean is significantly different from 14.44

c) $12.50 -2.01 \frac{4.75}{\sqrt{51}}= 11.163$

$12.50 +2.01 \frac{4.75}{\sqrt{51}}= 13.837$

Step-by-step explanation:

Information given

$\bar X=12.50$ represent the mean for the daily iron intake

$s=4.75$ represent the sample deviation

$n=51$ sample size

$\mu_o =14.44$ represent the reference value

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

Part a

We want to test if the mean iron intake among the low-income group is different from that of the general population, the system of hypothesis would be:

Null hypothesis: $\mu = 14.44$

Alternative hypothesis: $\mu \neq 14.44$

Part b

Since we don't know the population deviation the statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got

$t=\frac{12.50-14.44}{\frac{4.75}{\sqrt{51}}}=-2.917$

The degrees of freedom are given by:

$df =n-1= 51-1=50$

Now we can calculate the p value taking in count the alternative hypothesis

$p_v =2*P(t_{50}$

Since the p value is lower than the significance $\alpha=0.05$ we have enough evidence to reject the null hypothesis and the true mean is significantly different from 14.44

Part c

The confidence interval would be given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$

For the 95% confidence interval we can find the critical value in a t distribution with 50 degrees of freedom and we got:

$t_{\alpha/2}= 2.01$

And replacing we got:

$12.50 -2.01 \frac{4.75}{\sqrt{51}}= 11.163$

$12.50 +2.01 \frac{4.75}{\sqrt{51}}= 13.837$

7 0

3 years ago