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3 years ago

Given f(x) and g(x) = f(x + k), use the graph to determine the value of k.

Mathematics

1 answer:

Gnesinka [82]3 years ago

6 0

It would be D since you need to move the f(x) up 4 units to match g(x)

ANSWER: D

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Approximate the value of 11−−√ to the nearest tenths place. Plot the approximation on the number line.

posledela

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.

<em>Approximate the value of </em> $\sqrt{11}$ <em> to the nearest tenths place. Plot the approximation on the number line.</em>

(Please have a look at the attached photo)

My answer:

The value nearest tenths place of $\sqrt{11}$ is: 3.3

Hope it will find you well.

5 0

3 years ago

a store is selling hats. All regular price hats are 20% off. Lisa, Carly, and Sam each find a hat to buy. Sandy finds a sun viso

Dominik [7]

$12.5*\frac{100-20}{100}=\frac{1000}{100}=\$10$

The price will be $10

3 0

3 years ago

-2(bx-5)=16<br> The value of x in terms of b is?<br> That value of x when b is 3?

grin007 [14]

Answer:

Step-by-step explanation:

Let's solve for b.

−2(bx−5)=16

Step 1: Add -10 to both sides.

−2bx+10+−10=16+−10

−2bx=6

Step 2: Divide both sides by -2x.

−2bx/−2x=6/−2x

b=−3x

Answer:

b=−3x

———————————————————

Let's solve for x.

−2(bx−5)=16

Step 1: Add -10 to both sides.

−2bx+10+−10=16+−10

−2bx=6

Step 2: Divide both sides by -2b.

−2bx/−2b=6/−2b

x=−3b

Answer:

x=−3b

Hope this helps you out

7 0

4 years ago

Ivan purchased stock in a company at an initial price of $8 per share. The share value reached $18 after 10 days and then began

Butoxors [25]

The quadratic equation that best represents his model of the relationship between stock value and time is given by:

$y = -0.0976(x - 10)^2 + 18, x \geq 0$

The graph is given at the end of the answer.

<h3>What is the equation of a parabola given it’s vertex?</h3>

The equation of a quadratic function, of vertex (h,k), is given by:

$y = a(x - h)^2 + k$

In which a is the leading coefficient.

In this problem, the maximum value was a share value of $18 after 10 days, hence the vertex is:

(h,k) = (10,18).

Thus:

$y = a(x - 10)^2 + 18$

Since the initial price was of $8 per share, we have that:

$8 = a(0 - 10)^2 + 18$

$-82a = 8$

$a = -\frac{8}{82}$

$a = -0.0976$

Hence the equation is:

$y = -0.0976(x - 10)^2 + 18, x \geq 0$

At the end of the answer, the sketch of the graph is given.

More can be learned about quadratic equations at brainly.com/question/24737967

6 0

3 years ago

Let $\mu$ and $\sigma^2$ denote the mean and variance of the random variable x. determine $e[(x-\mu)/\sigma]$ and $e{[((x-\mu)/\

Nezavi [6.7K]

$\mathbb E\left(\dfrac{X-\mu}{\sigma}\right)=\dfrac1\sigma\mathbb E(X)-\dfrac\mu\sigma=\dfrac{\mu-\mu}\sigma=0$

$\mathbb E\bigg(\left(\dfrac{X-\mu}\sigma\right)^2\bigg)=\dfrac1{\sigma^2}\mathbb E\left(X^2-2\mu X+\mu^2\right)=\dfrac{\mathbb E(X^2)-2\mu\mathbb E(X)+\mu^2}{\sigma^2}$
$=\dfrac{\mathbb E(X^2)-2\mu^2+\mu^2}{\sigma^2}=\dfrac{\mathbb E(X^2)-\mu^2}{\sigma^2}=\dfrac{\mathbb E(X^2)-\mathbb E(X)^2}{\sigma^2}$
$=\dfrac{\mathbb V(X)}{\sigma^2}=\dfrac{\sigma^2}{\sigma^2}=1$

3 0

4 years ago