All categories

2 years ago

A container holds 44 cups of water. how much is this in gallons

Mathematics

1 answer:

Zepler [3.9K]2 years ago

7 0

Answer:

44 cups = 27.5 gallons

Step-by-step explanation:

Using the conversion:

1 cup = 0.625 gallons

We can find what is 44 cups in gallons.

=> 1 cup = 0.625 gallons

=> 44 x 1 = 0.625 x 44

=> 44 cups = 0.625 x 44 gallons

=> 44 cups = 27.5 gallons

Therefore, 44 cups = 27.5 gallons.

Hoped this helped.

You might be interested in

COSUL LOTUUSEUMURITULE.

notsponge [240]

Answer:

The answer to your question is below

Step-by-step explanation:

I numbered the squares, see the picture below

Angle 3 and the angle given are vertical angles so they measure the same

angle 3 = 137°

The sum of the angles 1, 2, 3 and 137 equals 360°, so

angle 1 + 137 + angle 3 + 137 = 360

and angle 1 and 3 are vertical angles so angle 1 = angle 3

2angle 1 = 360 - 137 -137

2 angle 1 = 86

angle 1 = 86 /2

angle 1 = 43°

angle 2 = 43°

The angle given and the angle 5 are corresponding angles, they measure the same

angle 5 = 137°

Angle 5 and 6 are vertical angles, they measure the same

angle 6 = 137°

Angle 2 and angle 7 are corresponding angles, they measure the same

angle 7 = 43°

Angle 3 and angle 6 are corresponding angles

angle 6 = 137°

Angle 4 and 7 are vertical angle, so they measure the same

angle 4 = 43°

5 0

3 years ago

Read 2 more answers

A force of 60 N is used to stretch two springs that are initially the same length. Spring A has a spring constant of 4 N/m, and

goblinko [34]

Answer:

D:Spring A is 3 m longer than spring B because 15 – 12 = 3.

Step-by-step explanation:

In this question, you should remember the Hooke's Law in physics.

The Hooke's Law simply explains that the extension that occurs on a spring is directly proportional to the load applied on it.

The mathematical expression for this law is

$F=-kx$

where;

F= force applied on the spring

x = the extension on the spring

k= the spring constant which varies in spring.

The question will need you to calculate the extension on the springs A and B then compare the values obtained.

In spring A

Force, F=60N and spring constant ,k=4 N/m

To find the extension x apply the expression;

$F=-kx\\\\60=-4*x\\\\60=-4x\\\\\frac{60}{-4} =\frac{-4x}{-4} \\\\\\-15=x$

Here the spring extension is 15 m

In spring B

Force, F=60N and spring constant , k=5N/m

To find the extension x apply the same expression

$F=-kx\\\\60=-5*x\\\\60=-5x\\\\\\\frac{60}{-5} =\frac{-5x}{-5} \\\\\\-12=x$

Here the extension on the spring is 12 m

Compare

The extension on spring A is 3 m longer than that in spring B because when you subtract the value of spring B from that in spring A you get 3m

$=15m-12m=3m$

5 0

3 years ago

The youth group is going on a trip to the state fair. The trip costs $58. Included in that price is $12 for a concert ticket and

Ksivusya [100]

2x + 12 = 58 <== ur equation (cost of the trip)
2x = 58 - 12
2x = 46
x = 46/2
x = 23 <== price of 1 pass

6 0

3 years ago

Read 2 more answers

And the

matrenka [14]

Answer:

A) The legs are 9 & 12 inches.

B) The hypotenuse is 15 inches.

Hope that helps! :) <3

Step-by-step explanation:

8 0

3 years ago

Sin 75°(cot 75° + cot 60°) help me simplify this

leva [86]

(square root of 6)/ 3

7 0

3 years ago