Answer:
B. -38.2 m/s
Explanation:
Given parameters:
Time of fall = 4s
Unknown:
Final velocity of the rock = ?
Solution:
To solve this problem, we use the expression below;
V = U + gt
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity = 9.8m/s²
t is the time taken
Now, insert the parameters and solve;
V = 0 + (9.8 x 4) = 39.2m/s
Answer:
Yes it will move and a= 4.19m/s^2
Explanation:
In order for the box to move it needs to overcome the maximum static friction force
Max Static Friction = μFn(normal force)
plug in givens
Max Static friction = 31.9226
Since 36.6>31.9226, the box will move
Mass= Wieght/g which is 45.8/9.8= 4.67kg
Fnet = Fapp-Fk
= 36.6-16.9918
=19.6082
=ma
Solve for a=4.19m/s^2
Answer:
Force of kinetic friction, Fk = 6N
Explanation:
Given the following data;
Coefficient of kinetic friction, μ = 0.2
Normal force, Fn=30N
To find the Force of kinetic friction;
Mathematically, the force of kinetic friction is given by the formula;
Fk = μFn
Where;
- Fk represents the force of kinetic friction.
- μ represents the coefficient of friction.
- Fn represents the normal force.
Substituting into the equation, we have;
Fk = 0.2*30
Fk = 6N
Therefore, the force of kinetic friction is 6N.