Answer:
a)it increasing accelerates, constant acceleration, decreasing acceleration
b)6.66m/sec
Explanation:
b)speed=distance/time
The acceleration of the box as it slides down the ramp is 4.9 m/s².
<h3>
What is the acceleration of the box down the incline?</h3>
The acceleration of the box down the incline is determined by applying Newton's second law of motion as shown below;
F - Ff = ma
where;
- F is the parallel force on the box
- Ff is the frictional force on box = 0
- m is the mass of the box
- a is the acceleration of the box
F - 0 = ma
F = ma
mg sinθ = ma
g sinθ = a
where;
- g is acceleration due to gravity
- θ is the angle of inclination of the incline
a = 9.8 x sin(30)
a = 4.9 m/s²
Learn more about acceleration here: brainly.com/question/14344386
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Answer:
55kmh
Explanation:
first of all according to formula add both of the velocity and divide it by 2
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Answer:
The speed of the combined vehicles is 6.82m/s
Explanation:
Using the law of conservation of momentum which stayed that the sum of momentum of bodies before collision is equal to their sum of momentum after collision. After collision, both object moves with the same velocity.
Momentum = mass×velocity
Before collision:
Momentum of vehicle or mass 3000kg moving with velocity 25m/s
= 3000×25
= 75000kgm/s
Pa = 75000kgm/s
Momentum of vehicle with mass 2500kg moving with velocity of -15m/s
= 2500×-15
= -37500kgm/s
After collision:
Momentum = (3000+2500)V
Where v is their common velocity
Momentum after collision = 5500V
Based on the law:
75000+(-37500) = 5500V
75000-37500 = 5500V
37500 = 5500V
V = 37500/5500
V = 6.82m/s
