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3 years ago

What is a magnetometer and how does it work?

1 answer:

8 0

Magnetometers are widely used for measuring the Earth's magnetic field and in geophysical surveys to detect magnetic anomalies of various types. They are also used in the military to detect submarines.

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A bicyclist increases her speed from 4.0 m/s to 6.0 m/s. The combined mass of the bicyclist and the bicycle is 55 kg. How much w

11Alexandr11 [23.1K]

Kinetic energy of the horse and rider = 1/2 (mass) (speed)²

At 4.0 m/s : KE = 1/2 (55kg) (4 m/s)² = 440 joules

At 6.0 m/s : KE = 1/2 (55kg) (6 m/s)² = 990 joules

She increased the kinetic energy of herself and her vehicle by 550 joules,
so she must have put at least that much work into it.

4 0

4 years ago

Read 2 more answers

A 2000-kg truck is being used to lift a 400-kg boulder B that is on a 50-kg pallet A. Knowing the acceleration of the rear-wheel

anzhelika [568]

Answer:

(a) reaction at each front wheel is 5272N (upward)

(b) force between boulder and pallet is 4124N (compression)

Explanation:

Acceleration of the truck $a_{t$ = 1 m/ $s^{2}$ (to the left)

when the truck moves 1 m to the left, the boulder is B and pallet A are raised 0.5 m, then,

$a_{A}$ = 0.5 m/ $s^{2}$ (upward) , $a_{B}$ = 0.5 m/ $s^{2}$ (upward)

Let T be tension in the cable

pallet and boulder: ∑fy = ∑(fy)eff = 2T- ( $m_{A}$ + $m_{B}$ )g = ( $m_{A}$ + $m_{B}$ ) $a_{B}$

= 2T- (400 + 50)*(9.81 m/ $s^{2}$ ) = (400 + 50)*(0.5 m/ $s^{2}$ )

T = 2320N

Truck: $M_{R}$ = ∑( $M_{R}$ )eff: = $-N_{f}$ (3.4m) + $m_{T}$ (2.0m) - T (0.6m)= $m_{T} a_{T}$ (1.0m)

Nf = (2.0m)(2000 kg)(9.81 m/ $s^{2}$ )/3.4m - (0.6 m)(2320 N)/3.4m + (1.0 m)(2000 kg)(1.0 m/ $s^{2}$ ) = 11541.2N - 409.4N - 588.2N = 10544N

∑fy (upward) = ∑(fy)eff: $N_{f}$ + $N_{R}$ - $m_{T}$ g = 0

10544 + $N_{R}$ - (2000kg)(9.81 m/ $s^{2}$ ) = 0

$N_{R}$ = 9076N

∑fx (to the left) = ∑(fx)eff: $F_{R}$ - T = $m_{T} a_{T}$

$F_{R}$ = 2320N + (2000kg)(9.81 m/ $s^{2}$ ) = 4320N

(a) reaction at each front wheel:

1/2 $N_{f}$ (upward): 1/2 (10544N) = 5272N (upward)

(b) force between boulder and pallet:

∑fy (upward) = ∑(fy)eff: $N_{B}$ + $M_{B}$ g - $m_{B}$ $a_{B}$

$N_{B}$ = (400kg)(9.81 m/ $s^{2}$ ) + (400kg)(0.5 m/ $s^{2}$ ) = 4124N (compression)

3 0

4 years ago

Read 2 more answers

A 29.0-kg block is initially at rest on a horizontal surface. A horizontal force of 71.0 N is required to set the block in motio

Julli [10]

Answer:

(a) $\mu_s=0.25$

(b) $\mu_k=0.20$

Explanation:

According to Newton's second law:

$\sum F_y:N=mg\\\sum F_x:F_a=F_f$

Recall that the frictional force is related jointly with the coefficient of friction and normal force $F_f=\mu N$ . Replacing in the above equation, we get the coefficient of friction:

$F_a=\mu N=\mu mg\\\mu=\frac{F_a}{mg}$

(a) The coefficient of static friction is related with the force required to set the block in motion:

$\mu_s=\frac{71N}{29kg*9.8\frac{m}{s^2}}\\\mu_s=0.25$

(b) The coefficient of kinetic friction is related with the force required to keep the block moving with constant speed:

$\mu_k=\frac{56N}{29kg*9.8\frac{m}{s^2}}\\\mu_k=0.20$

3 0

3 years ago

PLS ANSWER FAST 15 POINTS

marusya05 [52]

Answer:

$the \: force \: between \: the \: objects \: doubles$

4 0

3 years ago

When the first periodic table of the elements was published, the elements were arranged by atomic mass. Although several element

sesenic [268]

"New information changed the understanding of the atom’s structure"

Whenever a scientific observation is made, it has to be verified and its interpretation over time may change due to understanding of the specific phenomenon. Scientists do not alter the observation in any way; instead, explanations are presented to fit the observations as best as possible.

8 0

3 years ago