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Rashid [163]
2 years ago
10

A city is building a fence around a rectangular playground if the perimeter of the playground is 104 feet and the length of one

side of the fence is 32 feet what is the width of the play ground
Mathematics
2 answers:
34kurt2 years ago
8 0

Answer:

20 ft

Step-by-step explanation:

We know that

Perimeter of rectangle = 2(l + w)

Let the width be w

=> 104 = 2(32 + w)

=> 104/2 = 32 + w

=> 52 = 32 + w

=> 52 - 32 = w

=> 20 = w

Hence z

Width of playground is 20 ft

laila [671]2 years ago
7 0

Answer:

<h2>20</h2>

Basic fact:

<em>perimeter is (one side x by 2) + (the other side x by 2)</em>

Step-by-step explanation:

To find the other side we have been already given the total which is 104

We have also been given one side which is 32

we need to times 32 by 2 which is 64

subtract 64 from 104 which is 40

divide 40 by 2 which is 20

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Please help me!
nikklg [1K]

Explanation:

The solution set for a system of equation is the set of points where the graphs of the equations intersect.

__

<h3>general case</h3>

A system will have <em>one solution</em> if there is a <em>single point of intersection</em> of the graphs of the equations.

A system will have <em>no solutions</em> if the graphs have <em>no points of intersection</em>.

A system will have an <em>infinite</em> number of <em>solutions</em> if the graphs <em>intersect at an infinite number of points</em>.

_____

<h3>linear equations</h3>

When the equations are linear equations, their graphs are straight lines. If the lines have different slopes, they must intersect at exactly one point: there will be one solution.

If the lines have the same slope, there are two possibilities:

  • the lines are parallel -- no solutions
  • the lines are coincident -- infinite solutions

The attached graph illustrates these cases.

  • the red and blue lines are the graphs of a system of equations with one solution. Those lines have different slopes
  • the blue and green lines are the graphs of a system of equations with no solution. Those lines are parallel.
  • The red and (dotted) purple lines are the graphs of a system of equations with infinite solutions. Those lines are coincident.

8 0
2 years ago
the point slope form of the equation of the line that passes through (-4 -3) and (12, 1) is y - 1 = 1/4 (x - 12). what is the st
Sergeeva-Olga [200]

Standard Form is ...

ax + by = c

where a ≥ 0, b > 0 (if a=0), and {a, b, c} are mutually prime integers (unless irrational numbers are involved).

You can get there from where you're starting in a couple of steps. Multiply by the least common denominator of any fractions. (Here, you multiply by 4.) Then put the variable terms on the opposite side from the constant term. Make sure the leading coefficient is positive.

... 4y -4 = x -12

... x -4y = 8 . . . . add 12-4y

8 0
3 years ago
Please help me solve this
RSB [31]

Step-by-step explanation:

a) f(1) = -1 → x = -1

b) g(1) = Undefined

c) f(x) = 1 → x= Undefined

d) g(x) = 1 → x= 5

8 0
3 years ago
alex baked 2.5 batches of brownies. But, 5 brownies burned! if he now has below 15 brownies, how many were in each batch.​
tangare [24]

Answer:

The number of brownies in each batch is less than 8.

Step-by-step explanation:

Baked batches of brownies = 2.5

Number of burned brownies = 5

Number of brownies left is less than 15  

So, the total number of brownies is less than 15 + 5 = 20  

Number of brownies in each batch is

n < 20/2.5

n < 8

So, the number of brownies in each batch is less than 8.

6 0
3 years ago
(a) The perimeter of a rectangular field is 310 m.
Softa [21]

Answer:

<h3 />

a. \boxed{ \bold{ \boxed{ \sf{width \: of \: rectangular \: field \:  = 71 \: meter}}}}

b. \boxed{ \bold{ \boxed{ \sf{length \: of \: rectangular \: painting \:  = 85 \: cm}}}}

Step-by-step explanation:

a. Given,

Perimeter of rectangular field ( P ) = 310 m

Length of the field ( L ) = 84 m

Width of the field ( W ) = ?

<u>Finding </u><u>the </u><u>width </u><u>of </u><u>the </u><u>rectangular</u><u> </u><u>field</u>

\boxed{ \sf{perimeter \: of \: rectangle = 2(l + w)}}

plug the values

⇒\sf{310 = 2(84 + w)}

Distribute 2 through the parentheses

⇒\sf{310 = 168 + 2w}

Swap the sides of the equation

⇒\sf{168 + 2w = 310}

Move 168 to right hand side and change it's sign

⇒\sf{2w = 310 - 168}

Subtract 168 from 310

⇒\sf{2w = 142}

Divide both sides of the equation by 2

⇒\sf{ \frac{2w}{2}  =  \frac{142}{2} }

Calculate

⇒\sf{w = 71 \: m}

Width = 71 meters

------------------------------------------------------------

2. Given,

Area of rectangular painting ( A ) = 5185 cm²

Width of the painting ( w ) = 61 cm

Length of the painting ( l ) = ?

<u>Finding </u><u>length </u><u>of </u><u>the </u><u>painting</u>

\boxed{ \sf{area \: of \: rectangle = l \times w}}

plug the values

⇒\sf{5185 = 61l}

Swap the sides of the equation

⇒\sf{61 \: l \:  = 5185}

Divide both sides of the equation by 61

⇒\sf{ \frac{61 \: l}{61}  =  \frac{5185}{61} }

Calculate

⇒\sf{l = 85} cm

Length = 85 cm

Hope I helped!

Best regards !!!

4 0
3 years ago
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