1. x^2 + 6x + 8 = 0 2. x^2 + 10x + 21 + 0 3. X^2 + 9x + 18 = 0
1 answer:
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Answer:
the 7th
0.007805 or 59 / 756
Step-by-step explanation:
To determine the Friday that he needed more pounds, determine the number of pounds he needed per dog for each Friday.
to do this, divide the total pounds by the number of dogs
on the 14th
3/8 ÷ 35 =
3/8 x 1/35 = 3/280
on the 7th
1/2 ÷ 27 =
1/2 x 1/27 = 1/54
to determine which fraction is larger multiply each by 100 to determine its percent
3/280 x 100 = 1.071
1/54 x 100 = 1.852
1/54 is larger. Thus, more pounds was needed on Friday the 7th
the difference between these fractions should be determined
-
=
= 59 / 756
The probability will be the area under the normal distribution 
from 24 to 32.
We normalize these so we can use the standard normal distribution
Typically we'd just use a computer to tell us the integral of the standard normal from -1 to 5/3. In the old days we'd use the z table. It tells us the normal integral from 0 to positive z.
We know the integral of the Gaussian from -1 to 1 standard deviation is 68%; from the z table we see the probability from 0 to 1 is half that, <span>0.34134. That will also be the integral from -1 to 0.
The z table says the integral from 0 to 5/3, 1.67, is </span><span>0.45254.
So our total probability, integral from -1 to 5/3, is
</span>
That's really from z=-1 to z=+1.67 so likely a bit off in the last couple digits.
We normalize these so we can use the standard normal distribution
Typically we'd just use a computer to tell us the integral of the standard normal from -1 to 5/3. In the old days we'd use the z table. It tells us the normal integral from 0 to positive z.
We know the integral of the Gaussian from -1 to 1 standard deviation is 68%; from the z table we see the probability from 0 to 1 is half that, <span>0.34134. That will also be the integral from -1 to 0.
The z table says the integral from 0 to 5/3, 1.67, is </span><span>0.45254.
So our total probability, integral from -1 to 5/3, is
</span>
That's really from z=-1 to z=+1.67 so likely a bit off in the last couple digits.