Please find the correct energy transformations for these

Given that benzaldehyde is a meta- director, in the same Marvin editor draw all three resonance structures for the carbocation i

Jlenok [28]

Answer:

The reaction of FeBr3/Br2 with benzaldehyde will yield a major product in which the -Br is attached to the benzaldehyde at the meta position.

Explanation:

In chemistry, resonance is a way of describing bonding in certain molecules or ions by the combination of several contributing structures into a resonance hybrid in valence bond theory. Resonance structures often explain the formation of certain major and minor products in organic chemistry reactions.

Aromatic aldehydes and ketones undergo electrophilic substitution reactions such as nitration, sulphonation and halogenation. Since the aldehydic group (-CHO) and ketonic group (-COR or -COAr) are electron-withdrawing, they are deactivating and m-directing.

In benzaldehyde, the ring becomes deactivated at ortho & para positions due to an electron withdrawing aldehyde group. Hence electrophilic substitution is favored at Meta position.

This implies that the reaction of FeBr3/Br2 with benzaldehyde will yield a major product in which the -Br is attached to the benzaldehyde at the meta position.

4 0

3 years ago

Liquid octane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 10.3 g of octane is m

dsp73

Answer:

$\large \boxed{\text{31.8 g CO}_{2}}$

Explanation:

We are given the masses of two reactants and asked to determine the mass of the product.

This looks like a limiting reactant problem.

1. Assemble the information

We will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.

MM: 114.23 32.00 44.01

2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 18H₂O

Mass/g: 10.3 69.

2. Calculate the moles of each reactant

$\text{Moles of C$_{8}$H$_{18}$} = \text{10.3 g C$_{8}$H$_{18}$} \times \dfrac{\text{1 mol C$_{8}$H$_{18}$}}{\text{114.23 mol C$_{8}$H$_{18}$}} = \text{0.090 17 mol C$_{8}$H$_{18}$}\\\\\text{Moles of O$_{2}$} = \text{69. g O}_{2} \times \dfrac{\text{1 mol O$_{2}$}}{\text{32.00 g O$_{2}$}} = \text{2.16 mol O$_{2}$}$

3. Calculate the moles of CO₂ from each reactant

$\textbf{From C$_{8}$H$_{18}$:}\\\text{Moles of CO$_{2}$} = \text{0.090 17 mol C$_{8}$H$_{18}$} \times \dfrac{\text{16 mol CO$_{2}$}}{\text{2 mol C$_{8}$H$_{18}$}} = \text{0.7214 mol CO}_{2}\\\\\textbf{From O$_{2}$:}\\\text{Moles of CO$_{2}$} =\text{2.16 molO$_{2}$} \times \dfrac{\text{16 mol CO$_{2}$}}{\text{25 mol O$_{2}$}} = \text{1.38 mol CO$_{2}$}\\\\\text{Octane is the limiting reactant because it gives fewer moles of CO$_{2}$.}$

4. Calculate the mass of CO₂

$\text{ Mass of CO$_{2}$} = \text{0.7214 mol CO$_{2}$} \times \dfrac{\text{44.01 g CO$_{2}$}}{\text{1 mol CO$_{2}$}} = \textbf{31.8 g CO}_\mathbf{{2}}\\\\\text{The reaction produces $\large \boxed{\textbf{31.8 g CO}_\mathbf{{2}}}$}$

5 0

4 years ago

27 Which energy conversion must occur in an operating electrolytic cell?

Vitek1552 [10]

<u> electrical energy to chemical energy</u>

5 0

3 years ago

What happens when you add more solute to a saturated solution

valkas [14]

Answer:

If you add more solute in a saturated solution, it will have no effect. Additional solute does not dissolve in a saturated solution.

Explanation:

If more solute is added and it does not dissolve, then the original solution was saturated. If the added solute dissolves, then the original solution was unsaturated. A solution that has been allowed to reach equilibrium but which has extra undissolved solute at the bottom of the container must be saturated.

5 0

4 years ago

Plz answer all of these question thanks

gogolik [260]

F
D
F
B
This should help

5 0

3 years ago