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miss Akunina [59]
3 years ago
9

What is the percent by mass of magnesium sulfate in MgSO4 · 7H2O?

Chemistry
1 answer:
ad-work [718]3 years ago
5 0
The breakdown of mass percentage of the elements is determined by dividing molar masses to the total molar mass of the compound (246.37 g/mol). There are four elements: for Mg: 9.87%, S:13.01%, H:5.69%, 71.44%. 
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Which is an example of a heterogeneous catalyst?
N76 [4]
An example of a heterogeneous catalyst is a catalytic converter. A catalytic converter is an emissions control device that converts toxic pollutants in exhaust gas to less toxic pollutants by catalyzing a redox reaction (oxydation or reduction). 
8 0
3 years ago
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Which is one characteristic that temperate marine and temperate continental climates have in common?
shepuryov [24]

Answer:

it doesn't have savanna climate which is mostly found in Africa content

3 0
3 years ago
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the half life of the radioactive element strontium-90 is 29.1 years. If 16 grams of strontium-90 are initially present, how many
8_murik_8 [283]

Answer:

4 g after 58.2 years

0.0156 After 291 years

Explanation:

Given data:

Half-life of strontium-90 = 29.1 years

Initially present: 16g

mass present after 58.2 years =?

Mass present after 291 years =?

Solution:

Formula:

how much mass remains =1/ 2n (original mass) ……… (1)

Where “n” is the number of half lives

to find n

For 58.2 years

n = 58.2 years /29.1 years

n= 2

or  291 years

n = 291 years /29.1 years

n= 10

Put values in equation (1)

Mass after 58.2 years

mass remains =1/ 22 (16g)

mass remains =1/ 4 (16g)

 mass remains = 4g

Mass after 58.2 years

mass remains =1/ 210 (16g)

mass remains =1/ 1024 (16g)

mass remains = 0.0156g

8 0
3 years ago
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Give the volume indicated. Be sure to include all significant figures.
miskamm [114]

Answer: -

71

Explanation: -

From the diagram, we see that volume goes from 70 to 75 in 5 markings.

Each marking is for 1.

It is the most accuracy possible as there is no smaller marking.

Significant figures expresses the required amount of accuracy.

Thus the volume indicated from the diagram is 71 .

8 0
3 years ago
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How many grams of fosforic acid (H3PO4) are required to prepare 500 mL of a 0.2 M solution?
navik [9.2K]

Answer:

Mass = 9.8 g

Explanation:

Given data:

Molarity of solution = 0.2 M

Volume of solution = 500 mL

Number of grams of phosphoric acid = ?

Solution:

First of all we will convert the volume milliliter to litter.

500 mL × 1 L/1000 mL

0.5 L

Molarity = moles of solute / volume in litter

0.2 M =  number of moles / volume in litter

Number of moles = 0.2 mol/L × 0.5 L

Number of moles = 0.1 mol

Number of grams:

Number of moles = mass/molar mass

Mass = number of moles × molar mass

Mass = 0.1 mol × 98 g/mol

Mass = 9.8 g

7 0
3 years ago
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