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gulaghasi [49]
3 years ago
5

When graphing (16, 32), (–10, 11), (4, –27), and (–7, –5), select the most appropriate scale for

Mathematics
1 answer:
Masja [62]3 years ago
3 0

Answer:

yuh

Step-by-step explanation:

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Solve the problem below
Sliva [168]

Answer:

T = 60 degrees

Step-by-step explanation:

The dotted line is the height so it is a right angle

We are able to use trig functions since this is a right triangle

cos T = adj side / hyp

cos T = a/b

cos T = 8 sqrt(2) / 16 sqrt(2)

cos T = 1/2

Taking the inverse of each side

cos^-1 ( cosT) = cos^-1 ( 1/2)

T = 60 degrees

3 0
3 years ago
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I need help I’m bad at math
Alina [70]
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].

The width of each rect. is 1/2.

The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.

The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:

{1.875, 2.5, 2.875}

Add these three areas together; you sum will represent the approx. area under the given curve on the given interval:  1.875+2.5+2.875 = ?
5 0
2 years ago
Help me pleaseeeeeeeeee
gayaneshka [121]
THE ANSWER IS A.....
7 0
3 years ago
Can you say where to put each in different places in your answer? Please and thank you.
maw [93]
Coefficients are y and x
Variables are the number with the letters
The terms are the numbers
8 0
2 years ago
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Find the line through
Kaylis [27]

Answer:

(\frac{1}{2},\frac{-1}{2},\frac{1}{2})

Step-by-step explanation:

We have been given the intersection coordinates:

(7,1,-6) and perpendicular to the line x=-1+t ,y=-2+t and z=-1+t

From the condition of perpendicularity we know:  

(7,1,-6)(x,y,z)

\Rightarrow 7x+y-6z=0

Now, we have given x=-1+t , y=-2+t and  z= -1+t

7(-1+t)+(-2+t)-6(-1+t)=0

-7+7t-2+t+6-6t=0

\Rightarrow -3+2t=0

2t=3

t=\frac{3}{2}

Now, substituting t in the given coordinates x,y and z we get:

x=-1+\frac{3}{2}=\frac{1}{2}

y=-2+\frac{3}{2}=\frac{-1}{2}

And z=-1+\frac{3}{2}=\frac{1}{2}



3 0
3 years ago
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