Answer:
T = 60 degrees
Step-by-step explanation:
The dotted line is the height so it is a right angle
We are able to use trig functions since this is a right triangle
cos T = adj side / hyp
cos T = a/b
cos T = 8 sqrt(2) / 16 sqrt(2)
cos T = 1/2
Taking the inverse of each side
cos^-1 ( cosT) = cos^-1 ( 1/2)
T = 60 degrees
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].
The width of each rect. is 1/2.
The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.
The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:
{1.875, 2.5, 2.875}
Add these three areas together; you sum will represent the approx. area under the given curve on the given interval: 1.875+2.5+2.875 = ?
Coefficients are y and x
Variables are the number with the letters
The terms are the numbers
Answer:
Step-by-step explanation:
We have been given the intersection coordinates:
(7,1,-6) and perpendicular to the line x=-1+t ,y=-2+t and z=-1+t
From the condition of perpendicularity we know:
Now, we have given x=-1+t , y=-2+t and z= -1+t
Now, substituting t in the given coordinates x,y and z we get:
And 
