Julio is putting a rectangular pool in his backyard. The length of

Mathematics

1 answer:

IrinaVladis [17]3 years ago

8 0

Answer: 17

Step-by-step explanation: Luckly, this question is multiple choice meaning that we could try all the solutions going backwords. We will start from 10. Since the length is 7 feet more than the width, we will do 10 - 7 to find the width. That gives you 3 and perimiter means we have to add up all the sides. 3 + 10 + 3 + 10 = 26 and 54 does not equal 54. Now we will do 17. 17 - 7 gives you 10. So, 17 + 10 + 17 + 10 = 54. 54 = 54 so your answer will be 17.

You might be interested in

Ronald measured a house and its lot and made a scale drawing. The front patio, which is 14 meters wide in real life, is 7 millim

zhannawk [14.2K]

Answer:

2 metre= 1millimetre

Step-by-step explanation:

From the measurement of the house The front patio, is 14 meters wide in real life, is 7 millimeters wide in the drawing

Real life= 14 meters

Drawing= 7 millimeters,

The scale he used is 2 metre= 1millimetre

Which means he magnify the drawing by scale of 2 metre to get the real life structure.

✓Let us clarify it

14 meters = 7 millimeters

2 metre= x millimeter

If we cross multiply

7 millimeters× 2 metre= 14 metre × X millimeters

Make X subject of the formula we have

X= 1millimetres

3 0

3 years ago

What is the y intercept of 8x+4y=16

amid [387]

4 is the correct answer

8 0

3 years ago

Complete the statement.

iren [92.7K]

Answer:

Step-by-step explanation:

Coz they all look the same on the sides

4 0

3 years ago

Expand (2x-5y)⁷ and find fourth form

elena55 [62]

Step-by-step explanation:

By binomial theorem,

T(r+1) = nCr * a^(r+1) * b^r

Term 4 = 7C3 * (2x)^4 * (-5y)^3 = 35 * (16x^4) * (-125y^3) = -70000x^4y^3.

3 0

3 years ago

Write 2350 million in standard form

AleksAgata [21]

we know that

Standard Form is also known as Scientific Notation, is a method of writing numbers that accommodates value excessively large or small to be suitably written in Standard Decimal Notation

in this problem we have

$2,350\ million$