Answer:
See below ~
Step-by-step explanation:
<u>(a) Mean of the data</u>
- 2.4 + 1.6 + 3.2 + 0.3 + 1.5 / 5
- 9/5
- <u>1.8</u>
<u></u>
<u>(b) New mean after each data point increased by 10</u>
- 12.4 + 11.6 + 13.2 + 10.3 + 11.5 / 5
- 59/5
- <u>11.8</u>
<u></u>
<u>(c) New mean after each data point doubled [from (b)]</u>
- 24.8 + 23.2 + 26.4 + 20.6 + 23 / 5
- 118/5
- <u>23.6</u>
Answer:
Second option: 81y^4 - 16x^2, the difference of squares
Step-by-step explanation:
(9y^2-4x)(9y^2+4x) is a special product named difference of squares, then we can apply this formula:
(a-b)(a+b)=a^2-b^2, with a=9y^2 and b=4x, then:
(9y^2-4x)(9y^2+4x)=(9y^2)^2 - (4x)^2
(9y^2-4x)(9y^2+4x)=(9)^2 (y^2)^2 - (4)^2 (x)^2
(9y^2-4x)(9y^2+4x)=81y^(2*2) - 16x^2
(9y^2-4x)(9y^2+4x)=81y^4 - 16x^2
Multiply both sides by c
X = d*c
Hi do u want me to give you the answer or give u the formula?
Answer:
Lily is correct.
An example of a working solution to this problem is: 6/3 + 1/2 + 4/8.
Step-by-step explanation:
An integer is essentially a whole number(is not a part), but with negative numbers as well. Given whole numbers from 1 to 9, This can be an integer because an integer <u>includes</u> whole numbers.
