Answer:
See the answer and the resolution below
Explanation:
The equation of the decomposition of magnesium carbonate is as follows:
Mg C03 (white solid) ---> C02 (gas) + Mg= (solid)
To calculate the mass of carbon dioxide produced, the weight of 1 mol of this and 1 mol of MgC03 is calculated. Then a simple rule of 3 is made.
Weight 1 mol of MgC03= Weight Mg + Weight C+ 3x(Weight 0)= 24,305g+ 12,017+3x (15,999)= 84, 318g/mol
Weight 1 mol of C02= Weight C + 2x(Weight 0)=12,017+2x (15,999)= 44, 008g/mol
84, 319 g MgC03------44,008g C02
36,0 g MgC03------X= (36,0 g MgC03x44,008g C02)/84, 319 g MgC03= 18,8 g C02
