Here, the three different notation of the p-orbital in different sub-level have to generate
The value of azimuthal quantum number (l) for -p orbital is 1. We know that the magnetic quantum number 
depends upon the value of l, which are -l to +l.
Thus for p-orbital the possible magnetic quantum numbers are- -1, 0, +1. So there will be three orbitals for p orbitals, which are designated as 
, 
and 
in space.
The three p-orbital can be distinguish by the quantum numbers as-
For 2p orbitals (principal quantum number is 2)
1) n = 2, l = 1, m = -1
2) n = 2, l = 1, m = 0
3) n = 2, l = 1, m = +1
Thus the notation of different p-orbitals in the sub level are determined.
The color, shape, volume, mass, etc.
4 x 
in dL will be 4 x 
<h3>Conversion from dL to cm^3</h3>
Recall that:
Deci =
Centi = 
Thus, 1 dl = 100 ml
This means that converting from dl to requires multiplying by 
.
Applying this principle, 4 x in dL to will be:
4 x x = 4 x
Therefore, 4 x dl will be 4 x
More on volume conversion can be found here:
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Answer:
<h3><em>
Please make sure to re-write this on your own so your teacher doesn't think that your cheating!</em></h3>
Explanation:
A neutral atom will have the same number of electrons does protons. Since it has 4 protons, it must have an atomic number of 4. (That will make it beryllium.) Since it has 4 protons and 5 neutrons, it has a mass number of 9.
So the answer is 9
The number of boxes is calculated by dividing the
total mass of hardware boxes by 1.00 kg
<h3>What is a hardware?</h3>
A hardware is a physical component of a system that can be touched and felt.
Because hardware are physical components, they always have a given mass.
Assuming, several hardware each of mass 1.00 kg is available to be chosen from.
Also, assuming that the sum total of the mass of all the hardware is known.
The number of boxes can be calculated as follows:
- total mass of hardware/1.00 kg
Therefore, the number of boxes is obtained by dividing the sum of the mass of the boxes by 1.00 kg.
Learn more about hardware and mass at: brainly.com/question/25698914
