Hello,
Let a the first, b the second and c the third.
a+b+c=53
b=a/3
c=2a
==>a+a/3+2a=53
==>10a/3=53
==>a=15.9
c=2*a=2*15.9=31.8
b=a/3=15.9/3=5.3
Proof: a+b+c=15.9+5.3+31.8=53
The second number is 5.3
Answer:
First, we need to calculate for x. Since,
MP = PN
Thus,
3x-4 = x+4
2x = 8
x = 4
Next, we calculate for MS
MS = 2x + 2 = 10
Since, MS = 2SQ
10 = 2SQ
Then,
SQ = 5 units
Therefore, the correct answer is B.
Answer:
For this case if we want to conclude that the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:

For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:
n>= 30
Step-by-step explanation:
For this case if we want to conclude that the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:

For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:
n>= 30
Answer:
The answer to your question is the third option
Step-by-step explanation:
See the picture below
a) In the picture we observe that the parabola was narrowed not widened, so this option is incorrect.
b) From the picture, we conclude that the graph was shifted right 2 units, not four, so this option is incorrect.
c) From the picture, we observe that this option is the correct one.
d) We observe in the picture that this graph was not reflected so this option is incorrect.