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Kruka [31]
3 years ago
6

Find the length of the third side. If necessary, write in simplest radical form.

Mathematics
1 answer:
AleksandrR [38]3 years ago
8 0

Answer:

6

Step-by-step explanation:

This is a right triangle, and so the Pythagorean Theorem applies.  The legs of this triangle are 3√3 and 3; squaring these gives us 9(3) = 27 and 9.  Then, this Theorem gives us the length of the hypotenuse as

h^2 = 27 + 9, or h^2 = 36, so that h, the length of the hypotenuse, must be 6.

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An item that is on sale for 40% off costs $66. What was the item's regular price?
IRINA_888 [86]
  • <em>Answer:</em>

<em>The regular price was $110</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em />

<em>60% .......... $66</em>

<em>100% ..........$ x</em>

<em>x = 100×66/60</em>

<em>=  6600/60</em>

<em>= $ 110</em>

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7 0
4 years ago
Solve: 2x -3 =6<br> Hey can someone please help me with this?
shepuryov [24]

Hey there!

Answer:\boxed{x=\frac{9}{2}}

Explanation:

2x-3=6

2x-3+3=6+3\\2x=9 Add 3 to both sides.

\frac{2x}{2}=\frac{9}{2} Divide both sides by 2.

x=\frac{9}{2}

Hope this helps!

\text{-TestedHyperr}

6 0
4 years ago
Read 2 more answers
An artist cuts 4 squares with side length x ft from the corners of a 12 ft-by-18 ft rectangular piece of sheet metal. She bends
Kruka [31]

Answer:

V=4x^3-60x^2+216x

Step-by-step explanation:

<u>Volume And Function s</u>

Geometry can usually be joined with algebra to express volumes as a function of some variable. The volume of a parallelepiped of dimensions a,b,c is

V=abc

Our problem consists in computing the volume of a box made with some sheet of metal 12 ft by 18 ft. The four corners are cut by a square distance x as shown in the image below .

If the four corners are to be lifted and a box formed, the base of the box will have dimensions (12-2x)(18-2x) and the height will be x. The volume of the box is

V=x(12-2x)(18-2x)

Operating and simplifying

V=4x^3-60x^2+216x

8 0
3 years ago
Which table shows a proportional relationship?
Charra [1.4K]

The fourth option would be the answer.

3 0
4 years ago
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R(x) = –x² + 3x s(x) = 2x + 1<br><br> (s – r)(x) =
natta225 [31]

r(x) = –x² + 3x

s(x) = 2x + 1

(s – r)(x) is simply the difference of these functions. Subtract r(x) from s(x):

(s - r)(x) = s(x) - r(x)

(s - r)(x) = 2x + 1 - (-x² + 3x)

(s - r)(x) = 2x + 1 + x² - 3x

(s - r)(x) = x² - x + 1

3 0
3 years ago
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