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german
2 years ago
8

For any number n>1, is

Mathematics
1 answer:
masya89 [10]2 years ago
8 0

A because the > symbol means greater so if n is on the open side that means its greater

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Use the digits 1,3,4,and 7 to create two whole numbers whose product is estimated to be about 600
blagie [28]
34 x 17  (round the 2 numbers)
30 x 20
   600

Also, 34 x 17 = 578, which rounds to 600


The answer is 34 and 17

7 0
3 years ago
Read 2 more answers
Select the assumption necessary to start an indirect proof of the statement. If 3a+7 < 28, then a<7.
pashok25 [27]
When applying indirect proofs, we assume the negation of the conclusion is true, and show that this assumption would lead to nonsense, or contradiction.

In our case we assume a is not smaller than 7, that is we assume a≥7.

a≥7 then, multiplying both sides by 3:
3a≥21, then, adding both sides 7:

3a+7≥28,

which is a contradiction because 3a+7 is smaller than 28.

So our assumption is wrong, which means the opposite of it is correct.


Answer: assume a≥7
7 0
3 years ago
It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0
2 years ago
Aaron deposits $8,000 into an account that earns 3% interest, compounded Annually. How much money will he have after 4 years
Lapatulllka [165]
The equation used for this problem is

F = P(1+i)ⁿ
where
F is the future worth
P is the present worth
i is the effective interest rate
n is the number of years

Substituting the values,

F = <span>$8,000(1 + 0.03)</span>⁴
F = $9,004.07

Thus, after 4 years, Aaron will have $9,004.07.
4 0
3 years ago
Anyone kno number 10
QveST [7]
We Can’t Really See It
3 0
2 years ago
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