A counter example is
f(x)=5x^5+2x^3+3x
g(x)=-5x^5-x^4+x^2-4
Then f(x)+g(x) = -x^4+2x^3+x^2+3x-4 which is a polynomial of degree 4.
So the answer is no. Counter-example is given above.
Answer:
a = 4.762203156
Step-by-step explanation:
Given:
ab^4 = 12 and a^5b^5 = 7776
Making the equations a subject of a;
a = 12/b^4 and a^5 = 7776/b^5
Finding fifth root on both sides of equation two;
a = ![\sqrt[5]{7776}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B7776%7D)
/b
You will get a = 6/b
Equating the two equations;
12/b^4 = 6/b
Multiplying both sides by b^4 gives:
b = ![\sqrt[3]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%7D)
= 1.25992105
We had that a = 12/b^4 so;
a = 12/1.25992105^4 = 12/2.5198421 = 4.762203156
First one is three i think
Answer:
8.4 in
Step-by-step explanation:
Solution:-
- We consider the large right angle triangle namely, " XVW "
- We will recall all the trigonometric ratios that are applicable to all right angled triangles.
- While we are dealing with trigonometric ratios we have the following terms that needs to be correlated with the given specific problem:
Hypotenuse ( H ): Side opposite to 90 degrees angle
Base (B): The side adjacent to the available angle ( θ )
Perpendicular (P): The side opposite to the available angle ( θ )
- We will go ahead and mark our respective sides as follows:
Angle ( θ ) : 34°
Hypotenuse ( H ) : XW = 15 in
Base ( B ) : VW
Perpendicular ( P ) : VX
- Now recall all the trigonometric ratios studied:
sin ( θ ) = P / H = VX / XW
cos ( θ ) = B / H = VW / XW
tan ( θ ) = P / B = VX / VW
- Now choose the appropriate trigonometric ratio with two values given and one ( VX ) that needs to be determined as follows:
sin ( θ ) = P / H = VX / XW
sin ( 34° ) = VX / 15
VX = 15*sin ( 34° )
VX = 8.387 .. ( 8.4 ) in
Answer:
c
Step-by-step explanation:
