All categories

2 years ago

WILL MAKE BRAINLIEST!!! what is the slope of each line?

Mathematics

2 answers:

Pavel [41]2 years ago

5 0

Answer:

The line has a slope of 2.

Step-by-step explanation:

We can see that this line intersects (-3, -4) and (-1, 0), so it's slope, Δy/Δx, will be:

(-4 - 0) / (-3 - (-1))

= -4 / -2

= 2

Scorpion4ik [409]2 years ago

4 0

The correct answer is d, 2

You might be interested in

Helloooo can someone help meeeeeeeee

Liono4ka [1.6K]

Answer:

Option B, $(48x^{8}y^{5})$

Step-by-step explanation:

Step 1: Simplify the exponent

$(12x^{2}y^{3})(2x^{3}y)^{2}$

$(12x^{2}y^{3})(2^{2}x^{3*2}y^{1*2})$

$(12x^{2}y^{3})(4x^{6}y^{2})$

Step 2: Simply the expression

$(12x^{2}y^{3}*4x^{6}y^{2})$

$(48x^{2+6}y^{3+2})$

$(48x^{8}y^{5})$

Answer: Option B, $(48x^{8}y^{5})$

8 0

2 years ago

Find the value of the variable

marissa [1.9K]

Answer:

x=13

Step-by-step explanation:

because they're alternate adjacent angles:

5x=78-x

6x=78

x=13

8 0

3 years ago

Which polynomial has factors of 4x – 7 and x + 4?

34kurt

B. because when you multiply the factors they will get B

6 0

3 years ago

Read 2 more answers

Yvette earns $3 for every 1/4 hour she works. what is her hourly rate of pay

Lunna [17]

Yvette's hourly rate of pay is $12.
3+3+3+3=12

7 0

2 years ago

The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.

tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that perpendicular lines have negative reciprocal slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

$\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}$

so, it passes through the midpoint of AB,

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)$

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}$

4 0

3 years ago