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saul85 [17]
2 years ago
7

Can someone help me i am stuck on my quetsion

Mathematics
1 answer:
LenaWriter [7]2 years ago
3 0

Fairly certain the answer is C

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Translate point P(3,3) left 1 unit and up 4 units. What are the coordinates of the image P’?
ANTONII [103]
The coordinates would be (2,7) you just have to move 1 left 4 up
3 0
3 years ago
Is the expression 2f + 4f + 2 – 3 equivalent to 6f – 1? 6f – 1 evaluated at f = 9 is 53. 2f + 4f + 2 – 3 evaluated at f = 9 is a
morpeh [17]
We have that

the expression 2f + 4f + 2 – 3-------> we can group it   (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]

if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17

<span>let's check it
</span>[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok
6 0
3 years ago
Read 2 more answers
Find the measure of b.
Alika [10]

Answer:

b = 55°

Step-by-step explanation:

The angle at the centre is twice the angle on the circle subtended by the same arc, then

a = 0.5 × 110° = 55°

Angles on the circumference subtended by the same arc are congruent, so

b = a = 55°

5 0
2 years ago
Whats the answer i need help
julia-pushkina [17]
Answer)3.5
1)minus 17.5-14=3.5
2)14+3.5=17.5
3)keep adding 3.5
6 0
3 years ago
2. The ratio of radii of two cylinders is 1:2 and heights are in the ratio 2:3. Find the ratio of their volumes.
Savatey [412]

Answer: \frac{1}{6} or 1:6

Step-by-step explanation:

The volume of a cylinder can be found with the following formula:

V=\pi r^2h

Where "r" is the radius and "h" is the height of the cylinder.

In this case, let be:

- V_1 the volume of one of this cylinders and V_2 the volume of the other one.

- r_1 the radius of the first one and r_2 the radius of the other cylinder.

- h_1 the height of one of them and h_2 the height of the other cylinder.

Then:

V_1=\pi r_1^2h_1\\\\V_2=\pi r_2^2h_2

Therefore, you know this:

\frac{V_1}{V_2} =\frac{\pi r_1^2h_1}{\pi r_2^2h_2}

Simplifying, you get:

\frac{V_1}{V_2} =\frac{ r_1^2h_1}{ r_2^2h_2}

Now, knowing the ratios given in the exercise, you can substitute them into the equation:

\frac{V_1}{V_2} =\frac{1^2*2}{ 2^2*3}

Evaluating, you get:

\frac{V_1}{V_2} =\frac{2}{ 4*3}\\\\\frac{V_1}{V_2} =\frac{2}{12}\\\\\frac{V_1}{V_2} =\frac{1}{6}

4 0
3 years ago
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