Help me please!!!!d. car a was 45 miles east of car b.
1 answer:
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Answer:
The relation between the time and the distance will be:
y = 15x
The graph of the equation y = 15x is attached below.
Step-by-step explanation:
We know that the equation of linear function in two variables in the slope-intercept form is
y = mx+b
where
- m is the rate of change or slope
- b is the y-intercept
Let y be the distance
Let t be the time
Given that the object moves 15 meters in 1 second.
Thus, the rate of change or slope = m = 15
As there is no initial condition in our case.
Thus the y-intercept b = 0
Now, substituting m = 15 and b = 0 in the linear function
y = mx+b
y = 15x + 0
y = 15x
Therefore, the relation between the time and the distance will be:
y = 15x
The graph of the equation y = 15x is attached below.
Examples:
Calculate the distance in 1 second
put x = 1 in the equation
y = 15(1) = 15 meters
Calculate the distance in 10 second
put x = 10 in the equation
y = 15(10) = 150 meters
Answer:
D. Obtuse.
Step-by-step explanation:
We are told that in
and
. We are asked to classify our given
.
We can see that angle M and angle P are acute angles as their measure is less than 90 degrees.
Let us find the measure of angle P using angle sum property of triangles, which states that sum of interior angles of a triangle is 180 degrees.
So we can set an equation as:
Upon substituting our given values we will get,
As measure of angle N is 98 degrees, so angle N is an obtuse angle.
Since a triangle having an angle that measures more than 90 degrees is called an obtuse triangle, therefore, is an obtuse triangle and option D is the correct choice.