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Juli2301 [7.4K]
3 years ago
15

ASAP HELP WILL MARK BRAINLIEST

Mathematics
1 answer:
OLEGan [10]3 years ago
3 0

Answer:

c(x)=(3/4)^x

(3/4)^-2= 16/9

(3/4)^-1 =4/3

(3/4)^0=1

(3/4)^1 = 3/4

(3/4)^2= 9/16

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Twice the sum of consecutive numbers n and n + 1 is 510. What is the smaller number?
guajiro [1.7K]

Answer:

The smaller number is 127

Step-by-step explanation:

Lets write the given problem in equation form

sum of consecutive numbers n and n + 1 = n + n + 1 = 2n + 1

now we find twice of the sum of consecutive numbers n and n + 1

2*(2n + 1) = 4n + 2

given that

twice the sum of consecutive numbers n and n + 1 is 510

thus,

4n + 2 = 510

=> 4n = 510 -2 = 508

=> n = 508/4 = 127

Thus, the numbers are n = 127

n+1 = 127 + 1 = 128

the smaller number is 127

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Answer:

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Step-by-step explanation:

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Combined like terms:

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