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White raven [17]
3 years ago
12

2.What is the weight of an object that has a mass of 5 kg?​

Physics
1 answer:
Artemon [7]3 years ago
4 0

Answer:

5 kg

or 11 lbs

Explanation:

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Una cantidad de aire se lleva del estado a al estado b siguiendo una trayectoria recta en una grafica PV como es mostrado en la
allochka39001 [22]

Answer:

El trabajo de frontera ejercido por el gas es 10,297.875 joules.

Explanation:

Supongamos que el gas se comporta idealmente y que el proceso es isotérmico y adiabático. El trabajo efectuado por el gas en el proceso equivale al área bajo la curva de la gráfica PV. Puesto que es una línea recta y que tanto la presión como el volumen son variables positivas, tenemos que esa área es la suma del rectángulo inferior (límite inferior de la presión) y el triángulo superior (entre los límites inferior y superior de la presión). Es decir:

W = P_{min}\cdot (V_{2}-V_{1})+\frac{1}{2}\cdot (P_{max}-P_{min})\cdot (V_{2}-V_{1}) (1)

Donde:

W - Trabajo de frontera ejercido por el gas, medida en joules.

V_{1}, V_{2} - Volúmenes del gas antes y después de la expansión, medidas en metros cúbicos.

P_{min} - Límite inferior de la presión del gas, medida en pascales.

P_{max} - Límite superior de la presión del gas, medida en pascales.

Si sabemos que V_{1} = 0.06\,m^{3}, V_{2} = 0.13\,m^{3}, P_{min} = 125,432\,Pa y P_{max} = 168,793\,Pa, entonces el trabajo de frontera ejercido por el gas es:

W = (125,432\,Pa)\cdot (0.13\,m^{3}-0.06\,m^{3})+\frac{1}{2}\cdot (168,793\,m-125,432\,m) \cdot (0.13\,m^{3}-0.06\,m^{3})

W = 10,297.875\,J

El trabajo de frontera ejercido por el gas es 10,297.875 joules.

8 0
2 years ago
What are the properties of transverse waves in physics
jarptica [38.1K]

Transverse wave, movement in which all focuses on a wave sway along ways at right edges to the course of the wave's development. Surface swells on water, seismic S (auxiliary) waves, and electromagnetic (e.g., radio and light) waves are instances of transverse waves. Waves come in two assortments.

8 0
3 years ago
Read 2 more answers
A solid object has a mass of 104 kg and a volume of 1,278 m3. What is its density? 0.081 kg/m3 12.29 g/cm3 132912.00 g/cm3 canno
REY [17]
The density is 81.4 g/m3. Before you start plugging numbers into the density formula (D=M/V), you should convert 104 kg to grams, which ends up being 104,000 grams. Then you can plug in the 104,000 grams and 1,278 m3 into the formula. When you divide the mass by the volume, you get a really long decimal, which you can round to 81.4 g/m3, or whatever place your teacher wants you to round to.
4 0
3 years ago
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RC time constant circuit if R 50 KOC-21 a TOSS c. 1.05 s . what is the expected RC value b. 10.55 d. 0.105 s
Afina-wow [57]

Answer:

Time constant of RC circuit is 0.105 seconds.

Explanation:

It is given that,

Resistance, R=50\ K\Omega=5\times 10^4\ \Omega

Capacitance, C=2.1\ \mu F=2.1\times 10^{-6}\ F

We need to find the expected time constant for this RC circuit. It can be calculated as :

\tau=R\times C

\tau=5\times 10^4\times 2.1\times 10^{-6}

\tau=0.105\ s

So, the time constant for this RC circuit is 0.105 seconds. Hence, this is the required solution.

7 0
3 years ago
Which of the following creates an adhesive force that prevents separation of the parietal and visceral pleurae during ventilatio
Diano4ka-milaya [45]

Answer:

Negative intrapleural pressure is the correct answer

Explanation:

Intrapleural pressure is more subatmospheric in the uppermost part of the thorax than in the lowermost parts in the standing horse.

Air moves from a region of higher pressure to one of lower pressure.  Therefore, for air to be moved into or out of the lungs, a pressure difference between the atmosphere and the alveoli must be established. If there is no pressure difference, no airflow will occur.

Under normal circumstances, inspiration is accomplished by causing alveolar pressure to fall below atmospheric pressure. When the mechanics of breathing are being discussed, atmospheric pressure is conventionally referred to as 0 cm H2O, so lowering alveolar pressure below atmospheric pressure is known as negative-pressure breathing.

3 0
3 years ago
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