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olga2289 [7]
3 years ago
10

A Review | Constants Periodic Table

Physics
1 answer:
Marina86 [1]3 years ago
8 0
Rggtvtvtftvtgtvtbtbtbyvtvtvyvyvyb

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A red laser from the physics lab is marked as producing 632.8-nm light. When light from this laser falls on two closely spaced s
BARSIC [14]

Answer:

The wavelength is  \lambda_R  =  649 *10^{-9}\ m

Explanation:

From the question we are told that

   The wavelength of the red laser is  \lambda_r  =  632.8 \ nm =  632.8 *10^{-9}\ m

    The spacing between  the fringe is  y_r  =  6.00\ mm =  6.00*10^{-3}  \  m

   The spacing between  the fringe for smaller laser point  is  y_R   = 6.19 \ mm =  6.19 *10^{-3} \  m

      Generally the spacing between  the fringe is mathematically represented as

       y  =  \frac{D *  \lambda  }{d}

Here  D is the distance to the screen

    and  d is the distance of the slit separation

Now for both laser red light light and  small laser  point  D and  d are same for this experiment

So

         \frac{y_r}{\lambda_r}  =  \frac{D}{d}

=>      \frac{y_r}{\lambda_r}  = \frac{y_R}{\lambda_R}

Where \lambda_R  is the wavelength produced by the small laser pointer

  So

           \frac{6.0 *10^{-3}}{ 632.8*10^{-9}}  = \frac{ 6.15 *10^{-9}}{\lambda_R}

=>       \lambda_R  =  649 *10^{-9}\ m

7 0
3 years ago
A parallel-plate capacitor consists of two plates, each with an area of 27 cm^2 separated by 3.0 mm. The charge on the capacitor
aev [14]

Answer:

Explanation:

Capacity of a parallel plate capacitor  C = ε₀ A/ d

ε₀ is permittivity whose value is 8.85 x 10⁻¹² , A is plate area and d is distance between plate.

C =(  8.85 X10⁻¹² X  27 X 10⁻⁴ ) / 3 X 10⁻³

= 79.65 X 10⁻¹³ F.

potential diff between plate = Charge / capacity

= 4.8 X 10⁻⁹ / 79.65 X 10⁻¹³

= 601 V

Electric field = V/d

= 601 / 3 x 10⁻³

= 2 x 10⁵ N/C

Force on proton

= charge x electric field

1.6 x 10⁻¹⁹ x 2 x 10⁵

= 3.2 x 10⁻¹⁴

Acceleration a = force / mass

= 3.2 x 10⁻¹⁴ / 1.67 x 10⁻²⁷

= 1.9 x 10¹³ m s⁻²

Distance travelled by proton = 3 x 10⁻³

3 x 10⁻³ = 1/2 a t²

t = \sqrt{\frac{3\times2\times10^{-3}}{1.9\times10^{13}} }

t = 1.77 x 10⁻⁸ s

6 0
3 years ago
What is the maximum wavelength of incident light that can produce photoelectrons from silver? The work function for silver is Φ=
zalisa [80]

Answer:

4.24nm

0.385eV

Explanation:

Maximum wavelength (λmax) :

λmax = ( hc) /Φ

h = plancks constant = 6.63 * 10^-34

c = speed of light = 3*10^8

1ev = 1.6 * 10^-19

Φ = 2.93eV = 2.93* (1.6*10^-19) = 4.688*10^-19

λmax = [(6.63 * 10^-34) * (3 * 10^8)] / 4.688*10^-19

λmax = 19.89 * 10^-26 / 4.688*10^-19

λmax = 4.242 * 10^-7 m

λmax= 4.24nm

B.)

E = hc / eλ eV

λ = 3.75nm = 3.75 * 10^-7m = 375 *10^-9

E = (6.63 * 10^-34) * (3 * 10^8) / (1.6 * 10^-19) * (375 * 10^-9)

E = 19.89 * 10^-26 / 600 * 10^-28

E = 0.03315 * 10^-26 + 28

E = 0.03315 * 10^2

E = 3.315 eV

Stopping potential : (3.315 eV - 2.93eV) = 0.385eV

7 0
3 years ago
A car moves 8 km from home to school and then back to the home. a) Calculate the Distance covered by this car. b) What is the Di
Sveta_85 [38]

Explanation:

Distance covered = Total distance travelled by the car

Since the car travels to school and back to home again,

Total diatance covered = 8 + 8 = 16km

Displacement = Shortest distance between start point and destination.

Since, the car returns back to home from school,

the start and destination point are same.

So Displacement = 0

8 0
3 years ago
What are some possible results of constructive forces on earth's surface
Vitek1552 [10]

Answer:

what are the choices

Explanation:

4 0
3 years ago
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