Answer:
The correct answer is:
(a) 84.240 kg
(b) 24.038 m
Explanation:
The given values are:
Force,
F = 81.0 N
Distance,
S = 13.0 m
Time,
t = 5.20 s
As we know,
The acceleration of mass will be:
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
⇒ 
(a)
The mass of the block will be:
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
(b)
The final velocity after a given time i.e.,
t = 5.00 s
⇒ 
On substituting the values, we get
⇒ 
⇒ 
In time, t = 5.00 s
The distance moved by the block will be:
⇒ 
On putting the values, we get
⇒ 
⇒ 
Answer:
784 J
Explanation:
Work is force times distance.
W = Fd
W = mgd
W = (40 kg) (9.8 m/s²) (2 m)
W = 784 J
Answer:
F = 1.63 x 10⁻⁹ N
Explanation:
Complete question is as follows:
The diagram below shows two bowling balls, A and B, each having a mass of 7.0 kg, placed 2.00 m apart between their centers. Find the magnitude of Gravitational Force?
Answer:
The gravitational force is given by Newton's Gravitational Law as follows:
F = Gm₁m₂/r²
where,
F = Gravitational Force = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = m₂ = mass of each ball = 7 kg
r = distance between balls = 2 m
Therefore,
F = (6.67 x 10⁻¹¹ N.m²/kg²)(7 kg)(7 kg)/(2 m)²
<u>F = 1.63 x 10⁻⁹ N</u>
Answer:
V=14.9 m/s
Explanation:
In order to solve this problem, we are going to use the formulas of parabolic motion.
The velocity X-component of the ball is given by:
The motion on the X axis is a constant velocity motion so:
The whole trajectory of the ball takes 1.48 seconds
We know that:
Knowing the X and Y components of the velocity, we can calculate its magnitude by:
Answer:
the difference between the two is that the candle forms an emission spectrum and the book an absorption spectrum.
the book it is observed in all directions so that its reflection has to be diffused
Explanation:
The ray of light emitted by a candle is the light generated by the temperature of the flame, which is made up of the emissions of a black body at this temperature plus the emissions of the chemical elements that make up the candle.
The Light reflected from the cover of a book is the same incident light spectrum minus the wavelengths that create transitions in the elements of the cover, these wavelengths will be seen as dark areas.
As a consequence of the above, the difference between the two is that the candle forms an emission spectrum and the book an absorption spectrum.
For the cover of the book form a specular reflection the incident rays are reflected in one direction and the rest would be dark, but in the book it is observed in all directions so that its reflection has to be diffused
