1. in which lover of Earth are temperature and<br> pressure greatest?<br> 1-A<br> B <br> C <br> D

The engineer of a train traveling at 30 m/sec sees a cow on the tracks. He applies the brakes and causes the train to accelerate

sineoko [7]

Answer:The train travels 105 meters after applying the brakes

Explanation:If he decelerates 1.5 every minute, then he went from 28,5 m/s, to 27.0 m/s, to 25.5 m/s, to 24.0 m/s, after 4 seconds. Add all this together and youll get 105 meters moved in 4 seconds after he hit the brakes, I dont have a notebook on me though sorry :/

8 0

2 years ago

Skater 1 has a mass of 105.0 kg and a velocity of 2.0 m/s to the left. He

mart [117]

The final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

<h3>What is velocity?</h3>

Velocity can be defined as the ratio of the displacement and time of a body.

To calculate the final velocity of Skater 1 we use the formula below.

Formula:

mu+MU = mv+MV............ Equation 1

Where:

m = mass of the first skater
M = mass of the second skater
u = initial velocity of the first skater
U = initial velocity of the second skater
v = final velocity of the first skater
V = final velocity of the second skater.

make v the subject of the equation.

v = (mu+MU-MV)/m................ Equation 2

Note: Let left direction represent negative and right direction represent positive.

From the question,

Given:

m = 105 kg
u = -2 m/s
M = 71 kg
U = 5 m/s
V = -3.4 m/s.

Substitute these values into equation 2

v = [(105×(-2))+(71×5)-(71×(-3.4))]/105
v = (-210+355+241.4)/105
v = 386.4/105
v = 3.68 m/s
v ≈ 3.7 m/s

Hence, the final velocity of skater 1 is 3.7 m/s to the right. The right option is O A. 3.7 m/s to the right.

Learn more about velocity here: brainly.com/question/25749514

7 0

1 year ago

What is a true statement about the rotation period of the moon?

mrs_skeptik [129]

The time it takes for the Moon to rotate once around its axis is equal to the time it takes for the Moon to orbit once around Earth

5 0

2 years ago

A parallel-plate capacitor has plates of area A. The plates are initially separated by a distance d, but this distance can be va

ohaa [14]

Answer:

d' = d /2

Explanation:

Given that

Distance = d

Voltage =V

We know that energy in capacitor given as

$U=\dfrac{1}{2}CV^2$

$C=\dfrac{\varepsilon _oA}{d}$

$U=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d}\times V^2$

If energy become double U' = 2 U then d'

$U'=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d'}\times V^2$

$2U=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d'}\times V^2$

$2\times \dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d}\times V^2=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d'}\times V^2$

2 d ' = d

d' = d /2

So the distance between plates will be half on initial distance.

7 0

2 years ago

A trumpeter is placed on a moving sidewalk that moves at a constant velocity of 4.5 m/s. A listener is standing 6.0 m in front o

swat32

You didn't actually include the speed of sound. But it doesn't matter for this question. If the trumpeter and the listener are on the same moving sidewalk then the distance between them is not changing. The Doppler shift only happens when the distance between the source and the Observer is changing. So the Listener hears the same 290 Hertz that the trumpeter is generating.

7 0

3 years ago

1. in which lover of Earth are temperature and pressure greatest? 1-A B C D