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3 years ago

9th-grade geometry Find AB

Mathematics

2 answers:

Ksenya-84 [330]3 years ago

6 0

Answer:

d)AB = 12

Step-by-step explanation:

ΔADB ≅ ΔADC

⇒ AB ≅ AC {Corresponding parts of congruent triangles}

10x - 8 = 3x +6

Add 8 to both sides

10x = 3x + 6 + 8

10x = 3x + 14

Subtract 3x from both sides

10x - 3x = 14

7x = 14

Divide both sides by 7

x = 14/7

x = 2

AB = 10x - 8

= 10*2 - 8

= 20 - 8

AB= 12

Julli [10]3 years ago

4 0

Answer:

AB=2

Step-by-step explanation:

10x-8=3x+6

7x-8=6

7x=14

x=2

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See attachment

Step-by-step explanation:

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4 years ago

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4 years ago

Suppose A, R, and B are collinear on AB, and AR:AB= 1/5. What are the coordinates of R?

AfilCa [17]

Answer:

R(1.6, 0)

Step-by-step explanation:

Use the formula, $(x, y) = (x_1 + k(x_2 - x_1), y_1 + k(y_2 - y_1))$ to find the coordinates of point R, that partition the lie segment AB into the ratio 1/5.

Let,

$A(1, -1) = (x_1, y_1)$

$B(4, 4) = (x_2, y_2)$

Thus, plug in the values as follows:

$R(x, y) = (1 + \frac{1}{5}(4 - 1), -1 + \frac{1}{5}(4 -(-1))$

$R(x, y) = (1 + \frac{1}{5}(3), -1 + \frac{1}{5}(4 + 1)$

$R(x, y) = (1 + \frac{1}{5}(3), -1 + \frac{1}{5}(5)$

$R(x, y) = (1 + \frac{3}{5}, -1 + \frac{5}{5})$

$R(x, y) = (\frac{5 + 3}{5}, -1 + 1)$

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The coordinates of point R, are (1.6, 0)

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