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2 years ago

A dental filling is 9 carats. what percent of the filling is gold?

Mathematics

2 answers:

Law Incorporation [45]2 years ago

5 0

Answer:

So i say maybe 35% - 39%

Step-by-step explanation:

At 10 karats, the alloy is about 40% gold. At 20 karats, it's roughly 80%.

alexandr1967 [171]2 years ago

3 0

Answer:

Lower than 50%

Step-by-step explanation:

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(9x + 7)(4x + 1)(3x + 4) = 0 1 root 3 roots 4 roots 9 roots

asambeis [7]

Answer:

3 roots

Step-by-step explanation:

(9x+7)(4x+1)(3x+4)=0

x=-7/9 or - 1/4 or - 4/3

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2 years ago

Which of the following is equal to √^3√5 5^1/3 5^1/6 5^2/3 5^3/2

svlad2 [7]

I think it’s number 3

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2 years ago

A study at a college in the west coast reveals that, historically, 45% of their students are minority students. if a random samp

Evgesh-ka [11]

100 percent because 45 % is always in between 30 and 50 %

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2 years ago

Unit 3 homework 6 Gina Wilson

Sonja [21]

Answer:

5) The equation of the straight line is 2 x - y + 1 =0

6) The equation of the straight line is x + y -5 =0

7) The equation of the straight line is 5 x + 6 y - 24 =0

8) The equation of the straight line is x - 4 y -4 =0

9) The equation of the parallel line is 3x + y -19 =0

Step-by-step explanation:

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (1,3) , ( -3,-5)

$m = \frac{-5-3 }{-3-1 } = \frac{-8}{-4} = 2$

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

$y - 3 = 2 ( x - 1 )$

y = 2x - 2 +3

2 x - y + 1 =0

The equation of the straight line is 2 x - y + 1 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (1,4) , ( 6,-1)

$m = \frac{-1-(4) }{6-1 } = \frac{-5}{5} = -1$

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

$y - 1 = -1 ( x - 4 )$

y - 1 = - x +4

The equation of the straight line is x + y -5 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (-12 , 14) , ( 6,-1)

$m = \frac{-1-(14) }{6+12 } = \frac{-15}{18} = \frac{-5}{6}$

$y - 14 = \frac{-5}{6} ( x - (-12) )$

6( y - 14 ) = - 5 ( x +12 )

6 y - 84 = - 5x -60

5 x + 6 y -84 + 60 =0

5 x + 6 y - 24 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (-4 , -2) , ( 4 , 0)

$m = \frac{0+2}{4 +4} = \frac{2}{8} = \frac{1}{4}$

$y - (-2) =\frac{1}{4} ( x - (-4) )$

4 ( y + 2) = x + 4

x - 4 y -4 =0

The equation of the line y = 3x + 6 is parallel to the line

3x + y + k =0 is passes through the point ( 4,7 )

⇒ 3x + y + k =0

⇒ 12 + 7 + k =0

⇒ k = -19

The equation of the parallel line is 3x + y -19 =0

4 0

2 years ago

What is the solution set of -|x|= -8? {8} {-8} {-8,8) no solution

Vsevolod [243]

....the answer is -8,8

6 0

2 years ago

Read 2 more answers