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DIA [1.3K]
2 years ago
7

Combine the following expressions 2√18x^3 - 3√8x^3 A. -√x B. 0 C.√x

Mathematics
1 answer:
rosijanka [135]2 years ago
8 0

This is what I have but it doesn't match with your answers

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Evaluate the expression 81÷ (14 − 5) × 2
Naddik [55]

Answer:

See below.

Step-by-step explanation:

81/(14-5)*2

81/9*2

9*2

18

-hope it helps

4 0
2 years ago
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Hi can anybody tell me the answer
MArishka [77]

<u>Answer</u>:

8x^5y^7

<u>Step by step explanation</u>

4 {x}^{2}  {y}^{3}  \times 2 {x}^{3}  {y}^{4}    \\ 4 \times  2 \times  {x}^{2}  \times  {x}^{3}  \times  {y}^{3}  \times y ^{4}  \\ 8 \times  {x}^{2 + 3}  \times  {y}^{3 + 4}  \\  =8 {x}^{5}  {y}^{7}

6 0
3 years ago
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Which equation is that of a circle with a center (7,-1) and radius of 4
Damm [24]

Answer:

htx

Step-by-step explanation:

6 0
3 years ago
Complete the following ordered pairs.<br> Y=-7x+8<br> (0,__)<br> (7,__)<br> (__,36)
Sonbull [250]

Answer:

Answers are in bold in explanation

Step-by-step explanation:

We are given the equation:

y = -7x + 8

The first x value is 0

y = -7(0) + 8

y = 8

(0, 8)

The next x value is 7

y = -7(7) + 8

y = -41

(7, -41)

Now we are given the Y value instead of X, so we do this:

36 = -7x + 8

Subtract 8 on both sides to leave -7x alone

28 = -7x

Divide by -7 on both sides to isolate x

-4 = x

(-4, 36)

8 0
3 years ago
Read 2 more answers
Find the equation for the line that passes through the point (1,-3) and that is parallel to the line with the equation 3/2x-2y=-
kondaur [170]

The equation for the line that passes through the point (1,-3) and that is parallel to the line with the equation \frac{3}{2}x - 2y = \frac{-17}{2} is:

y = \frac{3}{4}x - \frac{15}{4}

<h3><u>Solution:</u></h3>

Given that line that passes through the point (1, -3) and that is parallel to the line with the equation \frac{3}{2}x - 2y = \frac{-17}{2}

We have to find equation of line

<em><u>The slope intercept form is given as:</u></em>

y = mx + c

Where "m" is the slope of line and "c" is the y-intercept

Let us first find slope of line containing equation \frac{3}{2}x - 2y = \frac{-17}{2}

\frac{3}{2}x - 2y = \frac{-17}{2}

Rearrange the above equation into slope intercept form

\frac{3x}{2} + \frac{17}{2} = 2y\\\\y = \frac{3x}{4} + \frac{17}{4}

On comparing the above equation with slope intercept form y = mx + c,

m = \frac{3}{4}

So the slope of line containing equation \frac{3}{2}x - 2y = \frac{-17}{2} is m = \frac{3}{4}

We know that slopes of parallel lines are equal

So the slope of line parallel to line having above equation is also m = \frac{3}{4}

<em><u>Now let us find the equation of line having slope m = 3/4 and passes through point (1 , -3)</u></em>

Substitute m = \frac{3}{4} and (x, y) = (1 , -3) in slope intercept form

y = mx + c

-3 = \frac{3}{4}(1) + c\\\\c = -3 - \frac{3}{4}\\\\c = \frac{-15}{4}

<em><u>Thus the required equation of line is:</u></em>

substitute m = \frac{3}{4} and c = \frac{-15}{4} in slope intercept form

y = \frac{3}{4}x + \frac{-15}{4}\\\\y =\frac{3}{4}x - \frac{15}{4}

Thus the equation of line is found out

3 0
3 years ago
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