Answer:
Step-by-step explanation:
∵ The volume of the pyramid = 1/3 base area × height
∵ The base is equilateral Δ with side length 4
∴ The area of the bast = 1/4 × 4² × √3 = 4√3 units²
To get the height of the pyramid draw it from the vertex of the top of the pyramid ⊥ to the base on the centro-id of the base which divides the height of the triangle two ratio 2:1 from the vertex of the triangle
∵ The height of the base = √(4² - 2²) =√12 = 2√3
∴ 2/3 the height = 4√3/3 ⇒ (2:1 means 2/3 from the height)
∴ The height of the pyramid = √[4² - (4√3/3)²] = √[16 - 48/9]
∴ h = 4√2/√3 (4√6/3 in its simplest form)
∴ V = 1/3 × 4√3 × 4√2/√3 = 16√2/3 units³
∴ 
Answer:
(-2,-2)
Step-by-step explanation:
solve by elimination
Perpendicular equation: y=-1/5x + 6
Answer:
length of 1 side of A, using the Pyth. Thm. and the dimensions of the other two squares: (side of A)^2 = (10 in)^2 + (24 in)^2. Then:
(side of A)^2 = 100+ 576 in^2 = 676 in^2.
Here I have not bothered to solve for the length of the side of A, since we want the area of square A. But if you do want the side length, find it: sqrt(676) = 26 in. Then the area of A is (26 in)^2 = 676 in^2.
Then the area of square A is (26 in)^2 =
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Step-by-step explanation:
So, since 100% = 128, x should equal 96, and we are trying to find x.
Multiply both sides of the equation by x.
(100/x) * x = (128/96) * x
Cancel out the x's on the left side so
100 = 1.333(x)
75 = x
96 is 75% of 128
