A^2+b^2=(a+b) (a-b)
Let a^2=x^2 then a^2= x^2
Let b^2=63 them b^2= 64
b=8
Answer: (x+8) (x-8)
7/438.... just solve it like thus.....EVERY FRACTION IS A DIVITION PROBLEM
First we have to know the Pythagoreans theorem which is
a^2+b^2=c^2
7^2+8^2=c^2
49+64= 10.63
Hope this helps
