T(t)=e−kt(∫ekt[KM(t)+H(t)+U(t)]dt+C)
M is the outside temperature, H is other things that affect temperature
in the tank(0 in this case), and U is the solar panel. K comes from the
time constant, and should be the inverse of the time constant I believe.
T is temperature, t is time.
T(t)=e−164t(∫e164t[164(80)+4t]dt
After integrating I keep getting
−16304+256t+Ce−164t
I calculate C to be 16414 setting t equal to 0 and using the initial conditions
Answer: 3.6
Step-by-step explanation:
½bh = 6.12
½ × 3.4 × b = 6.12
b = 6.12/ 1.7
Answer:
it's answer is y + 185 = 250; y = 65
hope it helps you
You could just subtract it or you could make it into a plus negative
