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galina1969 [7]
3 years ago
9

What is the surface area of the right trapezoidal prism? To receive credit, you must show the work used to arrive at a final ans

wer.

Mathematics
1 answer:
julia-pushkina [17]3 years ago
7 0

Answer:

210 cm²

Step-by-step explanation:

The net of the right trapezoidal prism consists of 2 trapezoid base and four rectangles.

Surface area of the trapezoidal prism = 2(area of trapezoid base) + area of the 4 rectangles

✔️Area of the 2 trapezoid bases:

Area = 2(½(a + b)×h)

Where,

a = 7 cm

b = 11 cm

h = 3 cm

Plug in the values

Area = 2(½(7 + 11)×3)

= (18 × 3)

Area of the 2 trapezoid bases = 54 cm²

✔️Area of Rectangle 1:

Length = 6 cm

Width = 3 cm

Area = 6 × 3 = 18 cm²

✔️Area of Rectangle 2:

Length = 7 cm

Width = 6 cm

Area = 7 × 6 = 42 cm²

✔️Area of Rectangle 3:

Length = 6 cm

Width = 5 cm

Area = 6 × 5 = 30 cm²

✔️Area of Rectangle 4:

Length = 11 cm

Width = 6 cm

Area = 11 × 6 = 66 cm²

✅Surface area of the trapezoidal prism = 54 + 18 + 42 + 30 + 66 = 210 cm²

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8 0
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The market and Stock J have the following probability distributions:
denis-greek [22]

Answer:

1) E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

2) E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

3) E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

4) E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

Step-by-step explanation:

For this case we have the following distributions given:

Probability  M   J

0.3           14%  22%

0.4           10%    4%

0.3           19%    12%

Part 1

The expected value is given by this formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

Part 2

E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

Part 3

We can calculate the second moment first with the following formula:

E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

Part 4

We can calculate the second moment first with the following formula:

E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

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qwelly [4]
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Answer with explanation:

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Option C

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3 years ago
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