What is the surface area of the right trapezoidal prism? To receive credit, you must show the work used to arrive at a final ans
1 answer:
Answer:
210 cm²
Step-by-step explanation:
The net of the right trapezoidal prism consists of 2 trapezoid base and four rectangles.
Surface area of the trapezoidal prism = 2(area of trapezoid base) + area of the 4 rectangles
✔️Area of the 2 trapezoid bases:
Area = 2(½(a + b)×h)
Where,
a = 7 cm
b = 11 cm
h = 3 cm
Plug in the values
Area = 2(½(7 + 11)×3)
= (18 × 3)
Area of the 2 trapezoid bases = 54 cm²
✔️Area of Rectangle 1:
Length = 6 cm
Width = 3 cm
Area = 6 × 3 = 18 cm²
✔️Area of Rectangle 2:
Length = 7 cm
Width = 6 cm
Area = 7 × 6 = 42 cm²
✔️Area of Rectangle 3:
Length = 6 cm
Width = 5 cm
Area = 6 × 5 = 30 cm²
✔️Area of Rectangle 4:
Length = 11 cm
Width = 6 cm
Area = 11 × 6 = 66 cm²
✅Surface area of the trapezoidal prism = 54 + 18 + 42 + 30 + 66 = 210 cm²
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Infinite solutions
hope this helps
A²+B²=C²
6²+8²=C²
C²=100
C=10
Therefore the length of AB is 10 units