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levacccp [35]
3 years ago
6

Sale

Mathematics
1 answer:
marissa [1.9K]3 years ago
6 0

Answer:

24

Step-by-step explanation:

25 is one-fourth of 100.

We can divide 32 by 4 and subtract that from 32.

32/4=8

32-8=24

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A tree is broken at a height of 35 m from the ground and its top touches the ground at a distance of 12 m from the base of the t
sergij07 [2.7K]
Original height of tree = (x+5) m
In triangle ABC x square = 5 square + 12 square
X square = 25+144
X square = 169
X = 13
Thus the original height of the tree was 13+15 = 18m
6 0
3 years ago
Solve the problem. Find the surface area of a right regular hexagonal pyramid with sides 2 cm and slant height 5 cm. Round youra
BabaBlast [244]

Answer:

The surface area of the right regular hexagonal pyramid is 50.78 cm².

Step-by-step explanation:

Given:

A right regular hexagonal pyramid with sides(s) 2 cm and slant height(h) 5 cm.

Now, to find the surface area(SA) of the right regular hexagonal pyramid.

So, we find the area of the base(b) first:

Area of the base = \sqrt[3]{3}\times s^{2}

                            = \sqrt[3]{3}\times 2^{2}

On solving we get:

Area of the base(b) = 20.784

Then, we find the perimeter(p) :

Perimeter = s × 6

p=2\times 6=12

Now, putting the formula for getting the surface area:

Surface area = perimeter × height/2 + Area of the base.

SA=\frac{p\times h}{2}+b

SA=\frac{12\times 5}{2}+20.784

SA=30+20.784

SA=50.784

As, <em>the surface area is 50.784 and rounding to nearest hundredth becomes 50.78 because in hundredth place it is 8 and in thousandth place it is 4 so rounding to it become 50.78.</em>

Therefore, the surface area of the right regular hexagonal pyramid is 50.78 cm².

5 0
3 years ago
I reallly need help for this
mel-nik [20]

Answer:

goals scored is 15

Step-by-step explanation:

As 60 goals scored in total and goaladinho scored a quarter of them so 60÷4=15

5 0
3 years ago
PLEASE HELP VERY URGENT!!!!!!!
Ierofanga [76]

Answer:

The correct option is;

C. (1.6, 1.3)

Step-by-step explanation:

Given that at x = 1.5 the y-values of both equations are y = 1.5 and y = 1 respectively

The x-value > The y-value

The difference in the y-values = 1.5 - 1 = 0.5

At x = 1.6 the y-values of both equations are y = 1.2 and y = 1.4 respectively

The x-value > The y-value

The difference in the y-values = 1.2 - 1.4 = -0.2

At x = 1.7 the y-values of both equations are y = 0.9 and y = 1.8 respectively

The x-value > The first y-value and the x-value < the second y-value

The difference in the y-values = 0.9 - 1.8 = 0.9

Therefore, the approximate y-value can be found by taking the average of both y-values when x = 1.6 where the difference in the y-values is least as follows;

Average y-value at x = 1.6 = (1.2 + 1.4)/2 = 1.3

Therefore, the best approximation of the exact solution is (1.6, 1.3)

By calculation, we have;

-3·x + 6 = 4·x - 5

∴ 7·x = 11

x = 11/7 ≈ 1.57

y = 4 × 11/7 - 5 ≈ 1.29

The solution is (1.57, 1.29)

8 0
3 years ago
HELP PLZ 3MINS ITS DUEE
Luden [163]

Answer:

11

Step-by-step explanation:

1/2 times 2³=4

+7=11

7 0
3 years ago
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