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Scrat [10]
3 years ago
8

If a box is not accelerating on a slope of 20 degrees, what is the net Force acting on the box?

Physics
1 answer:
never [62]3 years ago
3 0

Answer:

The net force is zero, if there is not external forces. The net force if the body is accelerating will be the product of the mass by the acceleration.

Explanation:

If the box does not accelerate, there are two possible options, either the box moves at constant velocity or does not receive any external force to alter its balance.

Newton's Second Law, also known as the Fundamental Law of dynamics, determines a proportional relationship between Force and variation of the amount of motion or linear moment of a body. In other words, The Force is directly proportional to the mass and acceleration of a body.

F=m*a\\where:\\m= mass [kg]\\a=acceleration[m/s^2]

0=m*a\\a=0[m/s^2]

If there are forces acting on the body and these forces are not in balance the body will move with a resulting force equal to the product of mass by acceleration.

F_{net} =m*a

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A car is traveling at the bottom of a 9.00-meter-radius circular hill with a constant speed v. The moment the car is at the bott
Rina8888 [55]

Answer:

Explanation:

reading of scale = reaction force of surface R

centripetal force = R - mg = m v² / R , m is mass , v is velocity and R is radius of the circular path .

R = mg + m v² / R

given ,

m v² / R = .80 mg

v² = .80 x g x R

= .8 x 9.8 x 9 = 70.56

v = 8.4 m /s

3 0
3 years ago
Which of the following statements about Gaussʹs law are correct? (There may be more than one correct choice.) Question 3 options
irina1246 [14]

Answer:

If a Gaussian surface is completely inside an electrostatic conductor, the electric field must always be zero at all points on that surface.

Explanation:

Option A is incorrect because, given this case, it is easier to calculate the field.

Option B is incorrect because, in a situation where the surface is placed inside a uniform field, option B is violated

Option C is also incorrect because it is possible to be a field from outside charges, but there will be an absence of net flux through the surface from these.

Hence, option D is the correct answer. "If a Gaussian surface is completely inside an electrostatic conductor, the electric field must always be zero at all points on that surface."

3 0
3 years ago
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seraphim [82]

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8 0
3 years ago
Suppose we have two planets with the same mass, but the radius of the second one is twice the size of the first one. How does th
bogdanovich [222]

The free-fall acceleration on the second planet is one-fourth the value of the first planet.

Calculation:

Consider the mass of planet A to be, M

               the mass of planet B to be, Mₓ = M

               the radius of planet A to be, R₁

               the radius of planet B to be, R₂

The acceleration due to gravity on planet A's surface is given as:

g = GM/R₁²      - (1)

Similarly, the acceleration due to gravity on planet B's surface is given as:

g' = GM/R₂²                           [where, R₂ = 2R₁]

   = GM/4R₁²    -(2)

From equation 1 & 2, we get:

g/g' = GM/R₁² ÷ GM/4R₁²

g/g' = 4/1

Thus we get,

g' = 1/4 g

Therefore, the free-fall acceleration on the second planet is one-fourth the value of the first planet.

Learn more about free-fall here:

<u>brainly.com/question/13299152</u>

#SPJ4

6 0
2 years ago
When a deck of cards slips out of your hands and falls to the ground, gravity<br> does work on it
motikmotik

Answer:

yes

Explanation:

3 0
3 years ago
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