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nalin [4]
3 years ago
10

A 0.187 A current flows through a wire. How much time will it take for 2.00 C of charge to flow past a point in the wire?

Physics
1 answer:
Oksana_A [137]3 years ago
7 0

Answer:A 0.187 A current flows through a wire. How much time will it take for 2.00 C of charge to flow past a point in the wire?

A. 10.7 s

B. 2.18 s

C. 0.374 s

D. 0.0935 s​

Explanation:

A 0.187 A current flows through a wire. How much time will it take for 2.00 C of charge to flow past a point in the wire?

A. 10.7 s

B. 2.18 s

C. 0.374 s

D. 0.0935 s​

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An electromagnetic wave with high frequency and high energy is A. Safe for humans. B. Is helpful to humans. C. Is helpful to hum
Vilka [71]
B and C are both correct choices.
4 0
4 years ago
What do you call the process of finding the magnitude of fy
MAVERICK [17]

Answer - vector resolution


Any vector suppose f if lies at some angle, then

fy = F x cos or sin (theta)

and fx =  F x cos or sin (theta)

Process of finding the value of component of any vector quantity is called Vector Resolution.

3 0
3 years ago
Read 2 more answers
A disk rotates freely on a vertical axis with an angular velocity of 30 rpm. An identical disk rotates above it in the same dire
Maslowich

Answer:

The final angular velocity of the disks is 25 rpm.

Explanation:

Given that,

Angular velocity \omega_{1}= 30\ rpm

Angular velocity \omega_{2}=20\ rpm

We need to calculate the angular velocity

Using formula of angular momentum

L=I\omega

Before the drop, the angular momentum of the system

L_{s}=I\omega_{1}+I\omega_{2}

L_{s}=I(\omega_{1}+\omega_{2})

L_{s}=I(30+20)

L_{s}=I(50\ rpm)....(I)

When both disk rotates together then the total moment of inertia is twice the inertia of one disk

L_{s}=2I\omega

From equation (I)

2I\omega=I\times50

\omega=25\ rpm

Hence, The final angular velocity of the disks is 25 rpm.

7 0
3 years ago
The dielectric in a capacitor serves two purposes. It increases the capacitance, compared to an otherwise identical capacitor wi
VikaD [51]

Answer: 580 x 10^-3 J

Explanation:

0.6mm is 0.6/1000 = 600*10^-6 m

The plate area is .17*.17 = 28.9*10^-3 m^2

Air:

The voltage that can be sustained by 0.60 mm of air dielectric is:

V = 3.0*10^6* 600*10^-6 = 1800 V

The capacitance is:

C = ε*A/d = 8.854*10^-12 * 28.9*10^-3/600*10^-6 = 426*10^-12 F = 426 pF

The energy stored in a capacitor is:

E = (1/2)*C*V^2 = (1/2)*426*10^-12*(1800)^2 = 691*10^-6 J

Teflon:

The voltage is:

V = 60*10^6* 600*10^-6 = 36*10^3 = 36 kV

According to the listed reference, the relative dielectric constant for teflon is 2.1, this figure multiplies the "ε" of free space.

The capacitance is:

C = ε*A/d = 2.1*8.854*10^-12 * 28.9*10^-3/600*10^-6 = 896*10^-12 F = 896 pF

It would have been easier to note that the capacitance is 2.1 times the air-dielectric case.

The maximum energy stored is:

E = (1/2)*C*V^2 = (1/2)* 896*10^-12* (36*10^3)^2 = 580*10^-3 J

8 0
3 years ago
Describe how turning off the electric current in an industrial electromagnet affects its magnetic field.
Mkey [24]

Answer:

turning off the electric current turns off the electromagnet

Explanation:

5 0
3 years ago
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