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Norma-Jean [14]
2 years ago
9

Sabriana hiked along a trail that was 9.66 miles long she hated 4.2 miles every hour how many hours did it take Sabriana to fini

sh hiking the trail
Mathematics
1 answer:
Fynjy0 [20]2 years ago
8 0

Answer:

3 hours

Step-by-step explanation:

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What is the commom difference in the following arithmetic sequence??
aalyn [17]
Each increases by a certain amount called the common difference

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6-4.4=1.6
7.7-6=1.7
hmm, some error
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answer is C
5 0
3 years ago
What is the distance between the points (5,2) and (-9,-2)?​
Tanya [424]
Between 5 and -9 it’s 14 units and between 2 and -2 it’s 4
6 0
3 years ago
Please help me fast and show all your work please thx ​
laiz [17]

Answer:

area of trapezoid/trapezium = \frac{h}{2} *(a+b)

h=height

a and b are the parallel sides (top 2.5 and bottom 6 in this pic)

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3 0
3 years ago
Read 2 more answers
A spider ate 25%25\% 25% 25, percent more bugs this month than last month. The spider ate 88 8 8 bugs last month. How many bugs
alekssr [168]

Answer:

10 bugs

Step-by-step explanation:

If last month the spider ate 8 bugs, and this month the spider ate 25% more bugs, we can calculate the amount of bugs the spider ate this month finding how much is 25% of 8 bugs, and them we sum this value to the 8 bugs it ate last month.

25% of 8 = 8 * 25 / 100 = 2

Now we know that the spider ate 2 more bugs, so the amount of bugs it ate this month is 8 + 2 = 10 bugs.

We can also solve this problem multiplying directly 8 by 1.25 (1.25 represents the 25% increase in the bug consumption):

8 * 1.25 = 10 bugs.

6 0
3 years ago
Please help! Identify the minimum value of the function y=3x^2-12x+10.
Dimas [21]
The lowest point is at the vertex, or U-turn.

\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{llccclll}
y = &{{ 3}}x^2&{{ -12}}x&{{ +10}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{-12}{2(3)}~~,~~10-\cfrac{(-12)^2}{4(3)} \right)\qquad \textit{so the lowest value is at }10-\cfrac{(-12)^2}{4(3)}
6 0
3 years ago
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