3 years ago

Can someone please help me on this ASAP!

Mathematics

1 answer:

kondaur [170]3 years ago

6 0

Answer:

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I NEED A LOT OF HELP PLEASE! I WILL FAIL IF IT DOESNT GET DONE!

Anna35 [415]

In order to solve for this, we need to find the volumes of both the cylinder and cone described.

In order to find the area of the cylinder:
We use the equation V= $\pi r^{2} h$
So, V= $\pi 6^{2}16$
The volume of the cylinder is therefore approximately <span>1809.56 $m^{3}$

For the cone:
V= $\pi r^{2} \frac{h}{3}$
So, V= $\pi 6^{2} \frac{3}{3}$
Thus, the volume of the cone is 113.1 $m^{3}$

We add these volumes together to derive the solution, which is 1922.66 $m^{3}$ </span>

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3 years ago

Please help il give u anything !!

makvit [3.9K]

Answer:

Step-by-step explanation:

Woah thats hard what year you in?

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Always add them all around and then divide the two and you should get the correct answer

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Um I think 4 i hope this helps

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