Answer:
A) an upper quartile of 56 and a median of 50
Step-by-step explanation:
Hello!
The lower and upper ends "box" from the box and whiskers plot is determined by the first (Q₁) and third (Q₃) quartiles of the data set and the line inside the box marks the median or second quartile of the sample (Q₂)
The length of the whiskers of the diagram is determined by the minimum value (left whisker) and the maximum value (right whisker)
If you observe the graphic:
Q₁= 42
Q₂= 50 (Median)
Q₃= 56
Min= 38
Max= 66
The box is delimited by a lower quartile of 42 and an upper quartile of 56, with a median 50, the least observation is 38 and the highest observation is 66.
The correct choice is A.
I hope this helps!
Answer:
The 50th term is 288.
Step-by-step explanation:
A sequence that each term is related with the prior by a sum of a constant ratio is called a arithmetic progression, the sequence in this problem is one of those. In order to calculate the nth term of a setence like that we need to use the following formula:
an = a1 + (n-1)*r
Where an is the nth term, a1 is the first term, n is the position of the term in the sequence and r is the ratio between the numbers. In this case:
a50 = -6 + (50 - 1)*6
a50 = -6 + 49*6
a50 = -6 + 294
a50 = 288
The 50th term is 288.
Answer:
9
Step-by-step explanation:
3 1/2/4=3 1/2*4=3 2=9
Answer:
9984000
Step-by-step explanation:
subtract the total by the other number (coverage)
Answer:
Step-by-step explanation:
if center=(h,k)
radius=r
eq. of circle is (x-h)^2+(y-k)^2=r^2
given eq. is (x-5)^2+(y+2)^2=16=4^2
comparing
center =(5,-2)
radius r=4
