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Mathematics

2 answers:

Alenkinab [10]2 years ago

6 0

Answer:

1. x-inter= 2

2. y-inter= -6

Step-by-step explanation:

Musya8 [376]2 years ago

3 0

Answer:

(0, -6) is the y-intercept, (2, 0) is the x-intercept

<u>Skill(s) needed: Standard Form Evaluation</u>

Step-by-step explanation:

1) We are using standard form in this problem here, where you have $Ax+By=C$

2) Now, regarding the y-intercept, the y-intercept is when the line intersects with the y-axis, so when x=0.

----> $(0,y_1)$

3) In this scenario, we can plug in 0 for x, and solve for y to get the y-intercept. Let's see it below:

---> $27x-9y=54$

---> $27(0)-9y=54$

---> $0-9y=54$

---> $-9y=54$

---> $y=-6$

Above, y=-6, so the y-intercept is (0, -6) (Note: This coordinate point is verbally defined as: When x equals zero, y equals negative six)

-------------------------------------------------------------------------------------------------------------- The x-intercept works the same way, it is the intersection with the x-axis, and is when y=0.

Plugging it in:

$27x-9(0)=54 \\ 27x=54 \\ x=2$

x equals two, when y =0, so (2,0) is the x-intercept

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Intersection point of Y=logx and y=1/2log(x+1)

GalinKa [24]

Answer:

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

The Problem:

What is the intersection point of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ ?

Step-by-step explanation:

To find the intersection of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ , we will need to find when they have a common point; when their $x$ and $y$ are the same.