Answer:
A.
Step-by-step explanation:
you have to find the discriminant
b²-4ac for each equation
if discriminant < 0 no real solutions because will be negative under the squareroot whhan you try to find the roots
if discriminant = 0 there is only one solution
if discriminant > 0 two real solutions
for your given problems
A. discriminant =(-2)²-4*2*15 will be negative
Answer with Step-by-step explanation:
We are given that

We have to explain that why the function is discontinuous at x=2
We know that if function is continuous at x=a then LHL=RHL=f(a).

LHL=Left hand limit when x <2
Substitute x=2-h
where h is small positive value >0


Right hand limit =RHL when x> 2
Substitute
x=2+h


LHL=RHL=
f(2)=1

Hence, function is discontinuous at x=2
Hello!
Let’s do it step-by-step, shall we? Don’t worry! These problems can be a bit tricky but you’ll get it in no time! It’s really simple.
So, we have (-7)(-5)
This means that the problem will be multiplied because of the parentheses. They substitute the multiplication sign.
So, we have -7 (multiplied by) -5= 35
So your answer would be 35. Hope this helps :) and good luck!
ANSWER
P'(6,-1)
EXPLANATION
The mapping for a reflection in the line y=x is
The line y=x is the mirror line for a function and it's inverse.

The x and y coordinates swap position.
The reflection of point P(−1, 6) across the line y = x is
P'(6,-1)