Slope is -2/5 and the y-intercept is 100

Mathematics

1 answer:

Mrrafil [7]2 years ago

4 0

Answer:

$y=-\frac{2}{5}+100$

Step-by-step explanation:

With the given information, we can write the line equation in slope intercept form. $y=mx+b$

The slope, m, is -2/5

The Y-intercept, or b, is 100.

Replace m with -2/5 and b with 100.

$y=mx+b\\y=-\frac{2}{5}x+100$

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assume that women's heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. find the

drek231 [11]

Answer:

65.3658 inches

Step-by-step explanation:

Let X be the height of a woman randomly choosen. We know tha X have a mean of 63.6 inches and a standard deviation of 2.5 inches. For an x value, the related z-score is given by z = (x-63.6)/2.5. We are looking for a value $x_{0}$ such that $P(X < x_{0}) = 0.76$ , but, $0.76 = P(X < x_{0}) = P((X-63.6)/2.5 < (x_{0}-63.6)/2.5) = P(Z < (x_{0}-63.6)/2.5)$ , i.e., $(x_{0}-63.6)/2.5$ is the 76th percentile of the standard normal distribution. So, $(x_{0}-63.6)/2.5 = 0.7063$ , $x_{0} =63.6+(2.5)(0.7063) = 65.3658$ . Therefore, the height of a woman who is at the 76th percentile is 65.3658 inches.